We are given displacement = 20 meters.
Time given = 4.7 seconds.
Velocity = 4.3 m/s.
Please note : Velocity is a vector quantity. A vector quantity depends on magnitude and direction as well.
We are given magnitude of displacement = 20 meter and time 4.7 seconds but the direction is missing there.
If it would be in forward direction it would be positive and if it would be in backward direction, it would be of negative.
Therefore, <u>"B)the direction"</u> is correct option.
Answer:
next should be 2250 if my math is correct
Answer:
1. x = 10
2. x = 4
Step-by-step explanation:
I use the angle ABC method:
AB² + AC² = BC²
6² + 8² = x²
x = 10
AB² + AC² = BC²
3² + x² = 5²
x = 4
<em>H</em><em>O</em><em>P</em><em>E</em><em> </em><em>T</em><em>H</em><em>I</em><em>S</em><em> </em><em>H</em><em>E</em><em>L</em><em>P</em><em>S</em><em> </em><em>A</em><em>N</em><em>D</em><em> </em><em>H</em><em>A</em><em>V</em><em>E</em><em> </em><em>A</em><em> </em><em>N</em><em>I</em><em>C</em><em>E</em><em> </em><em>D</em><em>A</em><em>Y</em><em> </em><em><</em><em>3</em>

The last line is in vertex form, and can see the vertex is located at (2,1).
Answer:
(D) t^4
Step-by-step explanation:
You have defined ...
a3 = a2·a1
a4 = a3·(a2·a1) = a3²
a5 = a4·(a3·a2·a1) = a4² = (a3²)² = a3⁴
Then if a3 = t, a5 = t⁴