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schepotkina [342]
2 years ago
11

FIND THE VOLUME AND SURFACE AREA. MEASUREMENT IN cm. π = 22/7

Mathematics
1 answer:
Digiron [165]2 years ago
7 0

The volume of the right triangular prism is 153.30 cubic units if the base length of the prism is 8 units.

<h3>What is a triangular prism?</h3>

When a triangle is, stretch it out to produce a stack of triangles, one on top of the other. A triangular prism is a name given to this novel 3D object.

It is given that:

A right triangular prism with dimensions

As we know, the volume of the right triangular prism is given by:

Volume = (1/2)bhl

Here b and l are the base dimensions h is the height of the prism

From the trigonometric ratios:

h = 10sin(25) = 4.23 units

b = 10cos(25) = 9.06 units

l = 8 units

Volume = (1/2)(9.06)(4.23)(8)

Volume = 153.30 cubic units

Thus, the volume of the right triangular prism is 153.30 cubic units if the base length of the prism is 8 units.

Learn more about triangular prisms here:

brainly.com/question/16909441

#SPJ1

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Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega
AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

To find the simplified form of the given expression :

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2 ( using the property (ab)^m=a^m.b^m )

=(2^6)(3^{-12})\times (2^{-6})(3^4) ( using the property (a^m)^n=a^{mn}

=(2^6)(2^{-6})(3^{-12})(3^4) ( combining the like powers )

=2^{6-6}3^{-12+4} ( using the property a^m.a^n=a^{m+n} )

=2^03^{-8}

=\frac{1}{3^8} ( using the property a^{-m}=\frac{1}{a^m} )

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

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