1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Studentka2010 [4]
3 years ago
14

A factory can fill 225 bottles of orange juice each hour. Each bottle of orange juice contains 24 fluid ounces. Each bottle of j

uice sells for $5.50. How many fluid ounces of juice are filled in each 12-hour shift?
Mathematics
1 answer:
lozanna [386]3 years ago
8 0

Answer:

27 i think

Step-by-step explanation:

I divided them to make sure its right im not 100 percent sure tho

You might be interested in
Estimate 72.91 + 67.526 by first rounding each number to the nearest whole number
Vikentia [17]

Answer:

141

Step-by-step explanation:

First, you would round 72.91 to 73 because the number to the right of 7 is greater than or equal to 5, so you would round up. Same goes for 67.526. round both up to 73 and 68 then add. You would get an answer of 141 :)

8 0
2 years ago
Read 2 more answers
What will be the result of substituting 2 for x in both expressions below? One-half x + 4 x + 6 minus one-half x minus 2 Both ex
tiny-mole [99]

Replace x with 2 and solve each equation:

1/2(2) + 4 = 1 + 4 = 5

2+ 6 -1/2(2) -2 = 8-3 = 5

The answer is:

both expressions equal 5 when substituting 2 for x because the expressions are equivalent.

7 0
2 years ago
A store has 1173 pairs of socks. the socks are sold in packs of 4 pairs. how many packs of socks can the store sell?
Nadusha1986 [10]

Answer:

293 packs is the maximum the store can sell.

Step-by-step explanation:

Determine the number of packs that can be made with 4 pairs of socks.

(1173 pairs)/(4 pairs/pack) = 293.25 packs

We can't sell 0.25 pack (1 pair of socks), so drop that fraction to yield 293 full packs.  Donate the spare pair, so to speak, to the local IRS agent.

5 0
1 year ago
When creating a scatterplot, if the points are too close together to see the relationship, how could you adjust your graph?
Radda [10]
The correct answer for this question is this one: "B. increase your scale values"

<span>When creating a scatterplot, if the points are too close together to see the relationship, You adjust your graph by </span><em>increasing your scale values</em>
Hope this helps answer your question and have a nice day ahead.
5 0
3 years ago
Read 2 more answers
Write the equation of the parabola in vertex form.
stellarik [79]

well, looking at the picture of this vertically opening parabola, it has a vertex at 0,0 and it passes through 2,1 hmm ok

~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ y = a(x-0)^2+0\qquad \stackrel{\textit{we also know that}}{x=2\qquad y = 1}\qquad \implies 1=a(2-0)^2+0 \\\\\\ 1=4a\implies \cfrac{1}{4}=a~\hspace{10em} \boxed{y=\cfrac{1}{4}x^2}

8 0
2 years ago
Other questions:
  • Rudy took a test and earned a 92%. Camilo earned a 88% on the same test. If Rudy answered 46 questions correctly, how many more
    9·1 answer
  • W(x)=x^3 - 5x^2 + 8x - 4<br> I need the x and y intercepts and the behavior of this equation.
    11·1 answer
  • What’s the area of polygon w
    8·1 answer
  • Solve.<br> 2x + 6 ≥ -8<br><br> A.) x ≥ -8<br><br> B.) x ≤ -8<br><br> C.) x ≥ -5<br><br> D.) x ≤ -5
    7·1 answer
  • What goes into 9 and 14 evenly
    5·2 answers
  • G(x) = 5 – 2x<br> What is the domain of g?
    11·2 answers
  • What is the center and radius of the circle with the given equation x^2 + y^2 + 14x - 12y +69 = 0
    7·1 answer
  • Please help. It’s my last one (:
    14·1 answer
  • Plzz help due in 2 mins
    6·1 answer
  • A scale drawing of Jack's living room is shown below:
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!