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lawyer [7]
1 year ago
11

The side of a square is 3^2 inches. Using the area formula A = s2, determine the area of the square.

Mathematics
1 answer:
earnstyle [38]1 year ago
7 0

The area of the square would be; 512 square inches.

<h3>What is the area of a square?</h3>

The area of a square can be calculated as the square of the sides of a given figure.

The area of a square = side x side

We are given that:

A side of a square = (8)³/² inches.

To find the area of a square we use the formula as;

Area = s²

Now Substitute with the side length in the rule given to get the area as follows:

Area=(8)³/²)²

Area = 8³

Area = 512 square inches

Learn more about the area;

brainly.com/question/1658516

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A horse-drawn carriage tour company has found that the number of people that take their tour depends on the price charged per cu
jonny [76]

Answer:

Option B- The horse-drawn carriage tour company can expect to take in $5760 when the charge per customer is $60.

Step-by-step explanation:

Given :

The function c(x)=50+5x  represents price charged per customer where x is the number of $5 increases they charge over a rate of $50 per person.

The function p(x)=100-2x represents the number of customers expected for the day, where x is the number of $5 increases they charge over a rate of $50 per person.

To find : (p⋅c)(2) mean about the horse-drawn carriage tour company.

Solution :

(p.c) means we multiply the p(x) and c(x)

(p.c)(x)=p(x)\times c(x)

(p.c)(x)=(100-2x)(50+5x)

(p.c)(x)=5000+500x-100x-10x^2

(p.c)(x)=5000+400x-10x^2

Substitute the value of x=2

(p.c)(2)=5000+400(2)-10(2)^2

(p.c)(2)=5000+800-10(4)

(p.c)(2)=5800-40

(p.c)(2)=5760

The horse-drawn carriage tour company can expect to take in $5760.

The function c(x)=50+5x  represents price charged per customer.

For x=2

c(x)=50+5(2)  

c(x)=50+10  

c(x)=60

The charge per customer is $60.

Therefore, Option B is correct.

The horse-drawn carriage tour company can expect to take in $5760 when the charge per customer is $60.

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Answer:

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f^{-1} is given by the definition of log

\large f^{-1}(d)=2^d\;sec.

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