Answer:
5.00
Step-by-step explanation:
the price for 3 avacados is 3.00 because 6 are 10 if you divide 10 by 2 you get 5
Answer:
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Answer:
Option B- The horse-drawn carriage tour company can expect to take in $5760 when the charge per customer is $60.
Step-by-step explanation:
Given :
The function
represents price charged per customer where x is the number of $5 increases they charge over a rate of $50 per person.
The function
represents the number of customers expected for the day, where x is the number of $5 increases they charge over a rate of $50 per person.
To find : (p⋅c)(2) mean about the horse-drawn carriage tour company.
Solution :
(p.c) means we multiply the p(x) and c(x)




Substitute the value of x=2




The horse-drawn carriage tour company can expect to take in $5760.
The function
represents price charged per customer.
For x=2
The charge per customer is $60.
Therefore, Option B is correct.
The horse-drawn carriage tour company can expect to take in $5760 when the charge per customer is $60.
Answer:
2/5 = 4/10
4/10 = 40%
Explanation:
2/5 is a simplified fraction, and one of the bigger fractions it’s made by 4/10. Do you can use 4/10, but can also use 8/20, 20/50, 40/100, so on. Since we know that any fraction that of ten can be turned into a percentage easily (2/10=20%, 5/10=50%,9/10=%90), then 4/10 is equal to 40%. So 40% of the people in Jeremiah’s class are boys.
Answer:
a) 4.392317 mt
b) 9 seconds
c) 
Step-by-step explanation:
We have

where t is given in seconds and t in meters.
<em>a)How far has the point traveled 21 seconds after it started moving?</em>
By replacing t=21 in our equation we get

<em>b)If the point has traveled 3.16993 meters, how many seconds have elapsed since it started moving?</em>
We need to find a t such that f(t) =3.16993.
This can be accomplished by using the definition of 

<em>c)Write a function
that determines the number of seconds that have elapsed since the particle started moving in terms of the distance (in meters) the particle has traveled.</em>
is given by the definition of log
