You just find the domain and the range and that’s it!
Answer:
Circumference: 12π
Area: 36π
Step-by-step explanation:
The equation for the circumference of a circle is:
C = πd
Where C is the circumference and d is the diameter. Knowing this, we will be able to find the circumference by pugging in 12 for d.
C = 12π
And now we have found the circumference of the circle.
The equation for the area of a circle is:
A = πr²
Where A is the area and r is the radius. Remember that the diameter is double the radius, so we can find the radius:
12 = 2r
r = 6
Now that we know r, we can find the area of the circle:
A = π(6)²
A = 36π
Now we have found the area.
So the circumference is 12π and the area is 36π.
I hope you find my answer and explanation to be helpful. Happy studying.
None of your options, not via complete the square nor quadratic the formula.
Solve for x over the real numbers:
x^2 + 8 x + 9 = 0
x = (-8 ± sqrt(8^2 - 4×9))/2 = (-8 ± sqrt(64 - 36))/2 = (-8 ± sqrt(28))/2:
x = (-8 + sqrt(28))/2 or x = (-8 - sqrt(28))/2
sqrt(28) = sqrt(4×7) = sqrt(2^2×7) = 2sqrt(7):
x = (2 sqrt(7) - 8)/2 or x = (-2 sqrt(7) - 8)/2
Factor 2 from -8 + 2 sqrt(7) giving 2 (sqrt(7) - 4):
x = 1/22 (sqrt(7) - 4) or x = (-2 sqrt(7) - 8)/2
(2 (sqrt(7) - 4))/2 = sqrt(7) - 4:
x = sqrt(7) - 4 or x = (-2 sqrt(7) - 8)/2
Factor 2 from -8 - 2 sqrt(7) giving 2 (-sqrt(7) - 4):
x = sqrt(7) - 4 or x = 1/22 (-sqrt(7) - 4)
(2 (-sqrt(7) - 4))/2 = -sqrt(7) - 4:
Answer: x = sqrt(7) - 4 or x = -sqrt(7) - 4_____________________________________________________
Solve for x:
x^2 + 8 x + 9 = 0
Subtract 9 from both sides:
x^2 + 8 x = -9
Add 16 to both sides:
x^2 + 8 x + 16 = 7
Write the left hand side as a square:
(x + 4)^2 = 7
Take the square root of both sides:
x + 4 = sqrt(7) or x + 4 = -sqrt(7)
Subtract 4 from both sides:
x = sqrt(7) - 4 or x + 4 = -sqrt(7)
Subtract 4 from both sides:
Answer: x = sqrt(7) - 4 or x = -4 - sqrt(7)
Answer:
25 cm.
Step-by-step explanation:
If the hypotenuse is x cm long the 2 legs are x-5 and x-10 cm long.
So by the Pythagoras theorem:
x^2 = (x - 5)^2 + (x - 10)^2
x^2 = x^2 - 10x + 25 + x^2 - 20x + 100
x^2 - 30x + 125 = 0
(x - 5)(x - 25) = 0
x = 5, 25
We can discard x = 5 because that would make the lengths of the legs negative so the hypotenuse = 25 cm long.
X intercept : (5,0),(-3,0)
y intercept : (0,-15)
vertex: (1,-16)
i’m glad to help! mark me brainliest if i’m correct plss
