Answer:
Explanation:
Data given and notation
represent the sample mean
represent the standard deviation for the sample
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
State the null and alternative hypotheses.
We need to conduct a hypothesis in order to determine if the mean is lower than 5600, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:
(1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
Calculate the statistic
We can replace in formula (1) the info given like this:
Answer:
The project to accept is:
e. E
Explanation:
a) Data and Calculations:
Cost of capital = 10%
Mutually Exclusive Projects:
A B C E
Payback (years) 1 5 2 5
IRR 18% 20% 20% 12%
NPV (Millions) $40 $75 $35 $100
b) Project E should be preferred over all the other projects. It has the highest net present value (NPV) and its internal rate of return (IRR) is above the company's cost of capital. It surpasses projects A, B, and C in financial performance terms using time-value of money analysis.
Answer:
Annual depreciation= $4,000
Explanation:
Giving the following information:
The cost of the machine was $29,000. Its estimated residual value was $9,000 at the end of estimated 5-year life.
<u>To calculate the depreciation expense, we need to use the following formula:</u>
Annual depreciation= (original cost - salvage value)/estimated life (years)
Annual depreciation= (29,000 - 9,000)/5
Annual depreciation= $4,000
