How many 5th graders total. Take that number divide it by 5 to get your answer.
8x + 6y = 10 ----------- (1)
5x - 3y = 2.2 ---------- (2)
(2) x 2:
10 x - 6y = 4.4 --------(2a)
(2a) + (1)
18x = 14.4
x = 1.8 ------- sub into (1)
8 (1.8) + 6y = 10
14.4 + 6y = 10
6y = 10 - 14.4
6y = - 4.4
y = - 0.73
There is 1 set of solution to it. (Answer C)
Answer:
maybe 3.6?? i dont exactly know what the absolute deviation for 3 is but i have the standard deviation
Step-by-step explanation:
sorry
No one see the quadrilateral
This is the missing equation that models the hieght and is misssing in the question:
<span>h= 7cos(π/3 t)
</span>
Answers:
<span>a. Solve the equation for t.
</span>
<span>1) Start: h= 7cos(π/3 t)
</span>
2) Divide by 7: (h/7) = <span>cos(π/3 t)
</span>
3) Inverse function: arc cos (h/7) = π/3 t
4) t = 3 arccos(h/7) / π ← answer of part (a)
b. Find the times at which the weight is first at a height of 1 cm, of 3
cm, and of 5 cm above the rest position. Round your answers to the
nearest hundredth.
<span>1) h = 1 cm ⇒ t = 3 arccos(1/7) / π</span>
t = 1.36 s← answer
2) h = 3 cm ⇒ t = 3arccos (3/7) / π = 1.08s← answer
3) h = 5 cm ⇒ 3arccos (5/7) / π = 0.74 s← answer
c. Find the times at which the weight is at a height of 1 cm, of 3 cm, and of 5 cm below the rest position for the second time.
Use the periodicity property of the function.
The periodicity of <span>cos(π/3 t) is 6.
</span><span>
</span><span>
</span><span>So, the second times are:
</span><span>
</span><span>
</span><span>1) h = 1 cm, t = 6 + 0.45 s = 6.45 s ← answer
</span>
2) h = 3 cm ⇒ 6 + 1.08 s = 7.08 s← answer
3) h = 5 cm ⇒ t = 6 + 0.74 s = 6.74 s ← answer
