3 years ago

What is the perimeter of quadrilateral DOBC

Mathematics

1 answer:

rosijanka [135]3 years ago

7 0

No one see the quadrilateral

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4x/x+3 - 4x/x+6 <br> Please help me find the right answer thxs

Arisa [49]

Answer:

Step-by-step explanation:

For 4x/x+3, just cancel the x to get 4+3=7

For -4x/x+6, cancel the x to get -4+6=2

7+2=9

Hope this helps

6 0

3 years ago

What is the value of the expression |x + y| when x = –8 and y = –13?

Free_Kalibri [48]

|x+y| = |-8+(-13)| = |-8-13| = |-21| = 21

8 0

3 years ago

(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

8 0

3 years ago

I have to find f(3)

crimeas [40]

Answer:

Step-by-step explanation:

plug 3 into x

2(3)^2+(3)

2(9)+3

18+3

f(3)=21

4 0

3 years ago

Read 2 more answers

Given the first three terms of a linear sequence: 3x – 2;x+9; 2x + 5 Determine the value of x.

Yuliya22 [10]

Answer:

x = 5

Step-by-step explanation:

The difference between consecutive terms will be equal , then

a₂ - a₁ = a₃ - a₂ , that is

x + 9 - (3x - 2) = 2x + 5 - (x + 9) ← distribute parenthesis on both sides

x + 9 - 3x + 2 = 2x + 5 - x - 9 , simplify both sides

- 2x + 11 = x - 4 ( subtract x from both sides )

- 3x + 11 = - 4 ( subtract 11 from both sides )

- 3x = - 15 ( divide both sides by - 3 )

x = 5

5 0

3 years ago

Read 2 more answers