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Svetradugi [14.3K]
2 years ago
15

The equation models the height h in centimeters after t seconds of a weight attached to the end of a spring that has been stretc

hed and then released.
a. Solve the equation for t.

b. Find the times at which the weight is first at a height of 1 cm, of 3 cm, and of 5 cm above the rest position. Round your answers to the nearest hundredth.

c. Find the times at which the weight is at a height of 1 cm, of 3 cm, and of 5 cm below the rest position for the second time. Round your answers to the nearest hundredth.
Mathematics
1 answer:
Nady [450]2 years ago
5 0
This is the missing equation that models the hieght and is misssing in the question:

<span>h= 7cos(π/3 t)
</span>

Answers:

<span>a. Solve the equation for t.
</span>

<span>1) Start: h= 7cos(π/3 t)
</span>

2) Divide by 7: (h/7) = <span>cos(π/3 t)
</span>

3) Inverse function: arc cos (h/7) = π/3 t

4) t = 3 arccos(h/7) / π ← answer of part (a)



b. Find the times at which the weight is first at a height of 1 cm, of 3 cm, and of 5 cm above the rest position. Round your answers to the nearest hundredth.

<span>1) h = 1 cm ⇒ t = 3 arccos(1/7) / π</span>

t = 1.36 s← answer


2) h = 3 cm ⇒ t = 3arccos (3/7) / π =  1.08s← answer


3) h = 5 cm ⇒ 3arccos (5/7) / π = 0.74 s← answer



c. Find the times at which the weight is at a height of 1 cm, of 3 cm, and of 5 cm below the rest position for the second time.

Use the periodicity property of the function.

The periodicity of <span>cos(π/3 t) is 6.
</span><span>
</span><span>
</span><span>So, the second times are:
</span><span>
</span><span>
</span><span>1) h = 1 cm, t = 6 + 0.45 s = 6.45 s ← answer
</span>

2) h = 3 cm ⇒ 6 + 1.08 s = 7.08 s← answer


3) h = 5 cm ⇒ t = 6 + 0.74 s = 6.74 s ← answer



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