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Dmitrij [34]
3 years ago
5

Help me please I don’t know how to

Mathematics
1 answer:
Irina-Kira [14]3 years ago
4 0

Answer:

A: 22

Step-by-step explanation:

2The interquartile range begins at 45 and ends at 67. All you need to do is subtract 45 drom 67, and you get 22.

You might be interested in
What is the vertex of the function f(x) = x2 + 12x?
saul85 [17]

Answer:

6, - 36 )

Step-by-step explanation:

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

x = - \frac{b}{2a}

f(x) = x² + 12x ← is in standard form

with a = 1, b = 12, c = 0 , then

x = - \frac{12}{2} = - 6

Substitute x = 6 into f(x) for corresponding value of y

f(6) = 6² + 12(- 6) = 36 - 72 = - 36

vertex = (6, - 36 )

5 0
3 years ago
Read 2 more answers
A triangle has a hypotenuse of 153 centimeters and a leg of 72 centimeters what is the length of the other leg
Inga [223]
Pythagorean theorem = \sqrt{a^{2} + b^2 +c^2 }
Since you only have a^{2} and c^2 you change the equation to \sqrt{c^2 - a^2 = b^2}
Giving you \sqrt{153^2 - 72^2 = 135
4 0
3 years ago
PLEASE SHOW WORK !!!
Fed [463]
For this, you have to understand the ratios of a 30,60,90 triangle. The ratio(in order) is x, x(sqrt 3), 2x (following the 30,60,90 pattern y'know). Well, we know the length of the hypotenuse, 4.2, so let's use ratios to figure the other sides out. The ratio of AC is x and the ratio of AB is 2x, so 2x/2=x=2.1. One side down. BC has a ratio of x(sqrt 3). We already know x so we can substitute it in. We get 2.1(sqrt 3). To calculate the area, use the formula 1/2(bh). Inputting the values in, we get 1/2(2.1*(2.1(sqrt 3)). This can be calculated to around 3.82. To calculate the perimeter, take the sum of the sides. By adding the sides together, we get about 9.98. Hope you can now understand how to do these kinds of questions.
3 0
3 years ago
This is amazing and whare did you get this information from
MaRussiya [10]
What is this,no question here
4 0
3 years ago
Read 2 more answers
For non-zero denominators, simplify: <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3a%5E3-75a%7D%7Ba%28a%2B5%29%28a%2B5%29%7D" id=
Debora [2.8K]
\frac{3a^3-75a}{a(a+5)(a+5)}=\frac{3a(a^2-25) }{a(a+5)(a+5)}=\frac{3a(a - 5)(a+5) }{a(a+5)(a+5)} =\frac{3 (a - 5) }{ (a+5) }


8 0
4 years ago
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