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Tamiku [17]
3 years ago
14

On a school trip 1/5 of teachers classes will be going if there are 105 students in all his classes how many students will be on

the trip please help
Mathematics
1 answer:
vodomira [7]3 years ago
6 0

Answer:

The answer is 21 ,

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PLEASE HELP! THiS IS DUE!!!!!!!! I Will MAKE BRAINlST
9966 [12]

Answer:

\mathrm{26.\qua\:H\quad\:2 \dfrac{ 1  }{ 4  }\qua\:mi}

\mathrm{27.\qua\:D\quad\: 9\dfrac{ 1  }{ 8  }\qua\:lb}

\mathrm{28.\qua\:H\quad\:14.6}

\mathrm{29.\qua\:C\quad\:25\%}

\mathrm{30.\qua\:J\quad\:33.912\qua\ ft^{3} }

Step-by-step explanation:

26.

\mathrm{\dfrac{ 3  }{ 4  }\:mile\:per\:one\:hour}

\mathrm{To\:find\:how\:far\:Jet's\:cousin\:can\:walk\:in\:3\:hours\:,\:we\:multiply\:\dfrac{ 3  }{ 4  }\:by\:3}

3 \times   \dfrac{ 3  }{ 4  }

\mathrm{Express\: 3 \times   \left(  \dfrac{ 3  }{ 4  }    \right)\:as\:a\:singe\:fraction}

\dfrac{ 3 \times  3  }{ 4  }

\mathrm{Multiply\:3\:and\:3\:to\:get\:9}

\dfrac{ 9  }{ 4  }

\mathrm{Convert\:\dfrac{ 9  }{ 4  }\:to\:a\:mixed\:number}

2 \dfrac{ 1  }{ 4  }

\mathrm{So\:she\:can\:walk\:2 \dfrac{ 1  }{ 4  }\:miles\:in\:3\:hours}

27.

\mathrm{Since\:we\:want\:to\:find\:how\:many\:pounds\:both\:pumpkins\:weigh\:together,\:we\:have\:to\:add.}

5 \dfrac{ 3  }{ 4  }  +3 \dfrac{ 3  }{ 8  }

\mathrm{Turn\:both\:mixed\:fractions\:into\:improper\:fractions}

\dfrac{ 23  }{ 4  }  + \dfrac{ 27  }{ 8  }

\mathrm{Least\:common\:multiple\:of\:4\:and\:8\:is\:8}

\mathrm{Multiples\:of\:4}:\quad4,8,12,16,20

\mathrm{Multiples\:of\:8}:\quad8,16,24,32,40

\dfrac{ 23  }{ 4  }  + \dfrac{ 27  }{ 8  }

\mathrm{Convert\:  \dfrac{ 23  }{ 4  }   \:and\:  \dfrac{ 27  }{ 8  }   \:to\:fractions\:with\:denominator\:8}

\dfrac{ 23 \times  2  }{ 4 \times  2  }  + \dfrac{ 27  }{ 8  }

\mathrm{Simplify}

\dfrac{ 46  }{ 8  }  + \dfrac{ 27  }{ 8  }

\mathrm{Since\:  \dfrac{ 46  }{ 8  }\:and\:\dfrac{ 27  }{ 8  }\:have\:the\:same\:denominators,\:add\:them\:by\:adding\:their\:numerators}

\dfrac{ 46+27  }{ 8  }

\mathrm{Add\:46\:and\:27\:to\:get\:73}

\dfrac{ 73  }{ 8  }

\mathrm{Convert\:\dfrac{ 73  }{ 8  }\:to\:a\:mixed\:number}

9 \dfrac{ 1  }{ 8  }

\mathrm{Both\:pumpkins\:weighed\:9 \dfrac{ 1  }{ 8  }\:pounds\:all\:together}

28.

Since the question is asking us "How many more miles did Alyce travel than Jason", we have to subtract the miles Jason traveled from the miles Alyce traveled.

29.193-14.593

\mathrm{Subtract\:14.593\:from\:29.193\:to\:get\:14.6}

14.6

\mathrm{Alyce\:traveled\:14.6\:more\:miles\:than\:Jason}

29.

For this question, we must find "10 is what percent of 40"

The equation for this is:

\dfrac{ 10  }{ 40  }   \times  100

\mathrm{Simplify\:  \dfrac{ 10  }{ 40  }   \:to\:  \dfrac{ 1  }{ 4  }   }

\dfrac{ 1  }{ 4  }   \times  100

\mathrm{Multiply\:  \dfrac{ 1  }{ 4  }\:and\:100\:to\:get\:  \dfrac{ 100  }{ 4  }   }

\dfrac{ 100  }{ 4  }

\mathrm{Divide\:100\:by\:4\:to\:get\:25}

25

\mathrm{So\:she\:recieved\:a\:25\%\:off\:discount}

To check if this is correct, you can do the following below:

What is 25 percent (%) off $40?

Use the formula and replace the given values:

Amount Saved = Original Price x Discount % / 100. So,

Amount Saved = 40 x 25 / 100

Amount Saved = 1000 / 100

Amount Saved = $10

In other words, a 25% discount for an item with original price of $40 is equal to $10

 

30.

Given that the calculated volume of the drum is 37.68 ft³ and it is 90% full, it implies that the current volume is calculated as:

\mathrm{Current\:compacity} =  90 \%   \times  37.68

\mathrm{Turn\:90\%\:into\:a\:decimal}

\mathrm{Current\:compacity} =  0.9   \times  37.68

\mathrm{Multiply\:0.9\:and\:37.68\:to\:get\:33.912}

33.912

\mathrm{The\:current\:compacity\:of\:the\:drum\:is\:33.912\:ft^{3} }

8 0
2 years ago
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Point t is the MIDPOINT of point SV. find the location of V!
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Answer:

-1.5

Step-by-step explanation:

The distance between S and T is

4 - -7

4+7 = 11

Divide this in half to find the midpoint

11/2 = 5.5

Add this to point S to get the point itself

-7 + 5.5 = -1.5

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