A triangle has a base of x^1/3 m and a height of x^1/2 m. If the area of the triangle is 16 m^2, what are the base and height o
1 answer:
Area = (base times height) / 2
Can rewrite it as
A= b * h * 1/2
16 = (x^(1/3)) * ( x^(1/2)) * (1/2))
Multiply by 2 to simplify
32 = x^(1/3) * x^(1/2)
32=x ^(5/6)
X=64
Base = 4
Height = 8
Please look below at how you multiply variables that have fractions as exponents (you need to add the exponents, common denominator and all that)
Can rewrite it as
A= b * h * 1/2
16 = (x^(1/3)) * ( x^(1/2)) * (1/2))
Multiply by 2 to simplify
32 = x^(1/3) * x^(1/2)
32=x ^(5/6)
X=64
Base = 4
Height = 8
Please look below at how you multiply variables that have fractions as exponents (you need to add the exponents, common denominator and all that)
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