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fiasKO [112]
3 years ago
12

Ok so i need help with this the image is below

Mathematics
2 answers:
mihalych1998 [28]3 years ago
7 0

Answer:

The graph

Step-by-step explanation:

ELEN [110]3 years ago
4 0

Answer: the line shown in the graph is different

Step-by-step explanation:

You might be interested in
A triangle has side measures of 8, 13, 15. Are these the measures of a RIGHT Triangle?
Andreas93 [3]

Answer:

No.

Step-by-step explanation:

Since we know the side lengths of the triangle, we can figure out whether or not this is a Pythagorean triple.

Pythagorean theorem: a^2 + b^2 = c^2

a and b are both smaller than c.

So,

8^2 = 64.

13^2 = 169.

15^2 = 225.

64 + 169 = 233.

233 is not equal to 225.

Therefore, this is not a right triangle.

6 0
3 years ago
Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side
lorasvet [3.4K]

Answer:

Step-by-step explanation:

1.

cot x sec⁴ x = cot x+2 tan x +tan³x

L.H.S = cot x sec⁴x

       =cot x (sec²x)²

       =cot x (1+tan²x)²     [ ∵ sec²x=1+tan²x]

       =  cot x(1+ 2 tan²x +tan⁴x)

       =cot x+ 2 cot x tan²x+cot x tan⁴x

        =cot x +2 tan x + tan³x        [ ∵cot x tan x =\frac{ \textrm{tan x }}{\textrm{tan x}} =1]

       =R.H.S

2.

(sin x)(tan x cos x - cot x cos x)=1-2 cos²x

 L.H.S =(sin x)(tan x cos x - cot x cos x)

          = sin x tan x cos x - sin x cot x cos x

           =\textrm{sin x cos x }\times\frac{\textrm{sin x}}{\textrm{cos x} } - \textrm{sinx}\times\frac{\textrm{cos x}}{\textrm{sin x}}\times \textrm{cos x}

           = sin²x -cos²x

           =1-cos²x-cos²x

           =1-2 cos²x

           =R.H.S

         

3.

1+ sec²x sin²x =sec²x

L.H.S =1+ sec²x sin²x

         =1+\frac{{sin^2x}}{cos^2x}                       [\textrm{sec x}=\frac{1}{\textrm{cos x}}]

         =1+tan²x                        [\frac{\textrm{sin x}}{\textrm{cos x}} = \textrm{tan x}]

         =sec²x

        =R.H.S

4.

\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}} = \textrm{2 csc x}

L.H.S=\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}}

       =\frac{\textrm{sinx(1+cos x)+{\textrm{sinx(1-cos x)}}}}{\textrm{(1-cos x)\textrm{(1+cos x})}}

      =\frac{\textrm{sinx+sin xcos x+{\textrm{sinx-sin xcos x}}}}{{(1-cos ^2x)}}

     =\frac{\textrm{2sin x}}{sin^2 x}

      = 2 csc x

    = R.H.S

5.

-tan²x + sec²x=1

L.H.S=-tan²x + sec²x

        = sec²x-tan²x

        =\frac{1}{cos^2x} -\frac{sin^2x}{cos^2x}

        =\frac{1- sin^2x}{cos^2x}

        =\frac{cos^2x}{cos^2x}

        =1

     

       

8 0
3 years ago
Round this number to the nearest tenth.<br><br> 52.85
k0ka [10]

Answer:

52.9

numbers 0-4  the number stays the same

numbers 5-9 the number goes up one

6 0
3 years ago
A random number from 1 to 5 is selected
shutvik [7]

Answer:

Relative frequency of selecting a 2 = 8/50 = 0.16

Relative frequency of selecting a 3 = 14/50 = 0.28

Step-by-step explanation:

When we have a given experiment with given outcomes (such that each time that we perform the experiment, one outcome happens) the relative frequency of a given outcome is the quotient between the number of times that that outcome happened, and the total number of times that the experiment was performed.

Here the experiment is selecting a random number between 1 and 5, and it is performed 50 times.

Out of these 50 times, the outcome "2" appears 8 times.

Then the relative frequency of selecting the number 2 is:

f(2) = 8/50 = 0.16

And of these 50 experiments, the outcome "3" appears 14 times.

Then the relative frequency of selecting the number 3 is:

f(3) = 14/50  = 0.28

7 0
3 years ago
Is -10 bigger than -4???
Alex787 [66]

Answer:

No

Step-by-step explanation:

3 0
3 years ago
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