The cost of a senior citizen ticket is $15 and the cost of a student ticket is $12.
How did I get this?
We know that 6 citizen tickets and 7 student stickers sold for $174 the first day. And 10 citizen tickets and 14 student tickets sold for $318 the second day.
1. create two equations out of this: C= citizen cost per ticket and S = student cost per ticket.
6C + 7S = $174
10C + 14S = $318
2. Use process of elimination. Multiply the first equation by 2 because we want two variables to cancel out.
-12C - 14S = -$348
10C + 14S = $318
Combine like terms.
-2C = $30
Divide by -2 on both sides. The left side cancels out.
C = $30/-2
C = -$15 (In this case the negative doesn't matter)
C = $15 (cost of senior citizen ticket)
Plug the value of C into any of the two equations so we can get the value of S.
6($15) + 7S = $174
Distribute the 6 into the parenthesis.
$90 + 7S = $174
Subtract both sides by $90 and the left side will cancel out.
7S = $84
Divide both sides by 7.
S = $12
Student ticket: $12
Senior citizen ticket: $15
Answer:
X= 7
Step-by-step explanation:
Answer: 4th graph
Explanation:
3x _> 3
x _> 3/3
x _> 1
9x > 54
x > 6
We can write x like this:
1 <_ x < 6
Meaning that x is bigger or equal to 1 but less than 6
Answer: There are 4 people who only go to the game on Saturday.
Step-by-step explanation:
Let the number of people go on Saturday be n(A).
Let the number of people go on Sunday be n(B).
Since we have given that
n(A) = 8
n(B) = 12
n(A∪B) = 16
According to rules, we get that
So, n(only go on Saturday) = n(only A) = n(A) - n(A∩B) = 8-4 = 4
Hence, there are 4 people who only go to the game on Saturday.
