We are given 3 equations. Using these equations we can find f(h(2)).
h(x)=7x-5
h(2)=7(2)-5
h(2)=14-5
h(2)=9
f(x)=x^2-7
f(h(2))=(7x-5)^2-7
we know the answer for h(2) by now, so we can substitute for that.
f(9)=9^2-7
f(9)=81-7
f(9)=74
so f(h(2))=74
Answer: 24(2y−1)
Step-by-step explanation:
Factor 48y−24
48y−24
=24(2y−1)
Answer:
24(2y−1)
It is 54 I think idk I’m just trying to get started lol.
Answer:
40 years and 20 years
Step-by-step explanation:
Let the father's age be y and son's age x
Father is currently twice son's age i.e 2x
16 years ago, the son was (x-16) years old
the father was (y-16) or (2x-16) years old.........(i)
The second sentence states that the father was 6 times his sons age 16 years ago i.e 6(x-16)yrs old.............(ii)
Equating (i) to (II) gives 2x-16 = 6(x-16)
2x-16 = 6x-96
Collecting like terms, 96-16 = 6x-2x, 80 = 4x, x = 20
Therefore, son's age is 20years and fathers age is twice son's age = 40 years
