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3 years ago

PLEASE HELP‼️ 10 POINTS!!

Mathematics

2 answers:

Ulleksa [173]3 years ago

5 0

Answer:

y=-3x+3

Answer:

y=-3x+3

Answer:

y=-3x+3

Answer:

y=-3x+3

Answer:

y=-3x+3

Answer:

y=-3x+3

Answer:

y=-3x+3

Answer:

y=-3x+3

Answer:

y=-3x+3

Answer:

y=-3x+3

Savatey [412]3 years ago

3 0

Answer:

y=2/3x+5

Step-by-step explanation:

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Complete the pattern 5, 10, 30, 60, 180

saveliy_v [14]

5, 10, 30, 60, 180, 360, 1,080

5*2=10
10*3=30
30*2=60
60*3=180
180*2=360
360*3=1,080

6 0

3 years ago

Read 2 more answers

Which mathematician’s collected works are by far the largest

hjlf

Leonhard Euler, who published nearly 900 books.

6 0

3 years ago

What is the value of x?<br><br> Enter your answer in the box.

Art [367]

Answer:

46 degrees

Step-by-step explanation:

you know that if you add 134 and x it will equal a straight line or 180 degrees. So set it up as an addition problem.

134 + x =180 subt. 134 from both sides

x=180-134

x=46 degrees

3 0

3 years ago

Read 2 more answers

Element X decays radioactively with a half life of 11 minutes. If there are 870 grams of Element X, how long, to the nearest ten

serg [7]

Answer:

It would take 27.5 minutes the element to decay to 154 grams.

Step-by-step explanation:

The decay equation:

$\frac {dN}{dt}\propto -N$

$\Rightarrow \R\frac {dN}{dt}=-\lambda N$

$\Rightarrow \frac {dN}N=-\lambda dt$

Integrating both sides

$\Rightarrow \int \frac {dN}N=\int-\lambda dt$

$\Rightarrow ln|N|=-\lambda t+c$

When t=0, N= $N_0$ = initial amount

$ln|N_0|=-\lambda .0+c$

$\Rightarrow c=ln|N_0|$

$ln|N|=-\lambda t+ln|N_0|$

$\Rightarrow ln|N|-ln|N_0|=-\lambda t$

$\Rightarrow ln|\frac{N}{N_0}|=-\lambda t$

Decay equation:

$ln|\frac{N}{N_0}|=-\lambda t$

Given that, the half life of of element X is 11 minutes.

For half life, $N=\frac12 N_0$ , t= 11 min.

$ln|\frac{N}{N_0}|=-\lambda t$

$\Rightarrow ln|\frac{\frac12N_0}{N_0}|=-\lambda . 11$

$\Rightarrow ln|\frac12}|=-\lambda . 11$

$\Rightarrow -\lambda . 11=ln|\frac12}|$

$\Rightarrow \lambda =\frac{ln|\frac12|}{-11}$

$\Rightarrow \lambda =\frac{ln|2|}{11}$ [ $ln|\frac12|=ln|1|-ln|2|=-ln|2|$ , since ln|1|=0]

N=154 grams, $N_0$ = 870 grams, t=?

$ln|\frac{N}{N_0}|=-\lambda t$

$\Rightarrow ln|\frac{154}{870}|=-\frac{ln|2|}{11}.t$

$\Rightarrow t= \frac{ln|\frac{154}{870}|\times 11}{-ln|2|}$

=27.5 minutes

It would take 27.5 minutes the element to decay to 154 grams.

5 0

3 years ago

Please someone answer. Identify the vocabulary word that matches the picture.

miss Akunina [59]

Answer:

alternate interior angles

Step-by-step explanation:

The angles are alternate interior angles

They are between the parallel lines and on opposite sides of the transversal

5 0

3 years ago