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2 years ago

Which measure of center is the most appropriate for the data in Table 2 (Weight)? Give a reason for your answer.

Mathematics

2 answers:

antoniya [11.8K]2 years ago

7 0

Answer:

The mean and the median can be calculated to help you find the "center" of a data set. The mean is the best estimate for the actual data set, but the median is the best measurement when a data set contains several outliers or extreme values.

Step-by-step explanation:

AleksandrR [38]2 years ago

5 0

Mean because all of the data points are
fairly close and there aren't any outliers
(extreme values)

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3 years ago

The function C(x) = 12x + 600 represents the cost to produce x number of items. How many items should be produced

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3 years ago

Read 2 more answers

If R = 25 cm and S = 7 cm, what is the length of T?

Levart [38]

Answer: 24cm

Step-by-step explanation:

R = 25 cm

S = 7 cm

T = ?

The square of equals to the addition of the square of S and the square of T.

R^2 = S^2 + T^2

25^2 = 7^2 + T^2

T^2 = 25^2 - 7^2

T^2 = 625 - 49

T =✓576

T = 24cm

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3 years ago

Solve:<br><br><img src="https://tex.z-dn.net/?f=%5Cunderset%7Bx%5Crightarrow~3%7D%7B%5Clim%7D~%5Cdfrac%7B2x%5E2-18%7D%7Bx%5E2-3x

vodomira [7]

Hello, please consider the following.

$\displaystyle \lim_{x\rightarrow3}~\dfrac{2x^2-18}{x^2-3x} \\ \\ \\ =\lim_{x\rightarrow3}~\dfrac{2(x^2-3^2)}{x(x-3)} \\ \\ \\ =\lim_{x\rightarrow3}~\dfrac{2(x-3)(x+3)}{x(x-3)} \\ \\ \\ =\lim_{x\rightarrow3}~\dfrac{2(x+3)}{x} \\ \\ \\=\dfrac{2(3+3)}{3}\\ \\ \\=\dfrac{2*3*2}{3} =\Large \boxed{\sf \bf \ 4 \ }$