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2 years ago

8x+5=6x+19. Help me pleaseeeeeeeeeee

Mathematics

2 answers:

hammer [34]2 years ago

7 0

Answer:

7x=12

Step-by-step explanation:

8x+5=6x+19

8x=6x+14

2x=14 Divided by 2 Equals x=7

Nutka1998 [239]2 years ago

3 0

Answer:

hi there!

the answer to this question is x= 7

Step-by-step explanation:

you minus 6x on both sides to get 2x+5=19

then you minus 5 on both sides to get 2x=14

then you divide 2 on both sides to get x=7

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If X and Y are independent continuous positive random

Leni [432]

a) $Z=\frac XY$ has CDF

$F_Z(z)=P(Z\le z)=P(X\le Yz)=\displaystyle\int_{\mathrm{supp}(Y)}P(X\le yz\mid Y=y)P(Y=y)\,\mathrm dy$

$F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}P(X\le yz)P(Y=y)\,\mathrm dy$

where the last equality follows from independence of $X,Y$ . In terms of the distribution and density functions of $X,Y$ , this is

$F_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy$

Then the density is obtained by differentiating with respect to $z$ ,

$f_Z(z)=\displaystyle\frac{\mathrm d}{\mathrm dz}\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy=\int_{\mathrm{supp}(Y)}yf_X(yz)f_Y(y)\,\mathrm dy$

b) $Z=XY$ can be computed in the same way; it has CDF

$F_Z(z)=P\left(X\le\dfrac zY\right)=\displaystyle\int_{\mathrm{supp}(Y)}P\left(X\le\frac zy\right)P(Y=y)\,\mathrm dy$

$F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}F_X\left(\frac zy\right)f_Y(y)\,\mathrm dy$

Differentiating gives the associated PDF,

$f_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}\frac1yf_X\left(\frac zy\right)f_Y(y)\,\mathrm dy$

Assuming $X\sim\mathrm{Exp}(\lambda_x)$ and $Y\sim\mathrm{Exp}(\lambda_y)$ , we have

$f_{Z=\frac XY}(z)=\displaystyle\int_0^\infty y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy$

$\implies f_{Z=\frac XY}(z)=\begin{cases}\frac{\lambda_x\lambda_y}{(\lambda_xz+\lambda_y)^2}&\text{for }z\ge0\\0&\text{otherwise}\end{cases}$

and

$f_{Z=XY}(z)=\displaystyle\int_0^\infty\frac1y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy$

$\implies f_{Z=XY}(z)=\lambda_x\lambda_y\displaystyle\int_0^\infty\frac{e^{-\lambda_x\frac zy-\lambda_yy}}y\,\mathrm dy$

I wouldn't worry about evaluating this integral any further unless you know about the Bessel functions.

6 0

3 years ago

The equation of a parabola is 1/32 (y−2)2=x−1 .

Andru [333]

The given equation of parabola is

$\frac{1}{32} (y-2)^2 = x-1$

Which can also be written as

$x = \frac{1}{32} (y-2)^2 +1$

Here vertex (h,k) is (1,2)

And value of a is

$a = \frac{1}{32}$

Formula of focus is

$(h+ \frac{1}{4a} , k)$

Substituting the values of h,k and a, we will get

$(1+ \frac{1}{4*(1/32) } , 2} = (1+ 8,2) = (9,2)$

Therefore the correct option is the last option .

6 0

3 years ago

Read 2 more answers

What is the value of x? A) 10 B) 12 C) 15 D) 17

prohojiy [21]

Answer:

c) 15

Step-by-step explanation:

7 0

2 years ago

Fifty points to whoever can answer this question !! :D

julia-pushkina [17]

$-1\dfrac{1}{5}=-1\dfrac{1\cdot2}{5\cdot2}=-1\dfrac{2}{10}=-1.2\\\\Answer:\ \boxed{b.\ G}$

6 0

3 years ago

Read 2 more answers

Scarlett is working two summer jobs, making $13 per hour landscaping and making $8 per hour clearing tables. In a given week, sh

dolphi86 [110]

Answer:

The graph in the attached figure

Step-by-step explanation:

Let

x ----> the number of hours landscaping

y ----> the number of hours clearing tables

we know that

she can work a maximum of 12 total

$x+y\leq 12$ ----> inequality A

she must earn a minimum of $120

$13x+8y\geq 120$ ----> inequality B

Solve the system of inequalities by graphing

The solution is the triangular shaded area

see the attached figure

Remember that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (the ordered pair lie in the shaded area of the solution set)

One possible solution is the point (10,1)

The point (10,1) lie in the shaded area

That means

The number of hours landscaping is 10 and the number of hours clearing tables is 1

5 0

3 years ago