2)
2*120 + 2*3.14*40 = 240 + 251.2 = 491.2;
Answer:
Two trapezoids labeled V R A S and B U W D. Sides B U and V R contain one tick mark. Sides B D, U W, V S, and R A each contain two tick marks. Sides A S and W D each contain three tick marks. The angles represented by vertex letters U, B, R, and V each contain two tick marks. The angles represented by vertex letters D, W, S, and A each contain one tick mark.
Its 3,167 hope this helped
If you would like to simplify <span>4 + (-3) - 2 * (-6), you can do this using the following steps:
</span><span>4 + (-3) - 2 * (-6) = 4 - 3 + 2 * 6 = 1 + 12 = 13
</span>
The correct result would be 13.
Pairs, in this case, relates to a group of 2 or more. We have 6 friends. Let's call them A,B,C,D,E,F. This will allow us to make a [some sort of] combination tree:
1. ABC against DEF
2. ABD against CEF
3. ABE against CDF
4. ABF against CDE
5. ACD against BFE
6. ACE against BDF
7. ACF against BDE
8. ADE against BCF
9. ADF against BCE
10. AEF against BCD
I believe there are 12 combinations... I just can't think of the last 2 though.