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insens350 [35]
3 years ago
8

What is the distance from J To K

Mathematics
1 answer:
Maurinko [17]3 years ago
5 0

Answer:

C. 13 unit

Step-by-step explanation:

I got right

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Factor completely<br> 3x^2 + 7x - 6 <br><br><br> Zzz
Dmitrij [34]

Answer:

(3x−2)(x+3)

Step-by-step explanation:

these are ur answers

8 0
3 years ago
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A cable is <br> 40<br><br> meters long. How long is the cable in decimeters?
AnnyKZ [126]
Hello,

1 meter is equal to 10 decimeters.

SO, 
if we convert 40 meters to decimeters, we multiply 40 meters by 10 decimeters, getting 400 decimeters.

Hope this helps!

May
6 0
4 years ago
Use the given transformation x=4u, y=3v to evaluate the integral. ∬r4x2 da, where r is the region bounded by the ellipse x216 y2
exis [7]

The Jacobian for this transformation is

J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix} 4 & 0 \\ 0 & 3 \end{bmatrix}

with determinant |J| = 12, hence the area element becomes

dA = dx\,dy = 12 \, du\,dv

Then the integral becomes

\displaystyle \iint_{R'} 4x^2 \, dA = 768 \iint_R u^2 \, du \, dv

where R' is the unit circle,

\dfrac{x^2}{16} + \dfrac{y^2}9 = \dfrac{(4u^2)}{16} + \dfrac{(3v)^2}9 = u^2 + v^2 = 1

so that

\displaystyle 768 \iint_R u^2 \, du \, dv = 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2 \, du \, dv

Now you could evaluate the integral as-is, but it's really much easier to do if we convert to polar coordinates.

\begin{cases} u = r\cos(\theta) \\ v = r\sin(\theta) \\ u^2+v^2 = r^2\\ du\,dv = r\,dr\,d\theta\end{cases}

Then

\displaystyle 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2\,du\,dv = 768 \int_0^{2\pi} \int_0^1 (r\cos(\theta))^2 r\,dr\,d\theta \\\\ ~~~~~~~~~~~~ = 768 \left(\int_0^{2\pi} \cos^2(\theta)\,d\theta\right) \left(\int_0^1 r^3\,dr\right) = \boxed{192\pi}

3 0
2 years ago
Angle XYZ is rotated 270 degrees counterclockwise about the origin to form angle X’Y’Z’. Which statement shows the measure of an
8090 [49]
It is fine that you did not include the measure of angle XYZ in your posting.

This question is testing your knowledge of the four types of transformations.
1) Translations - an item is "slid" to a new location.
2) Reflections - an item is "flipped" (usually over the x-axis or y-axis)
3) Rotations - an item is rotated, usually around the origin (the point (0,0) is the center of most rotations, especially in high school math).
4) Dilations - an item is enlarged or reduced by a certain ratio.

It the first three, the image after the transformation is congruent to the pre-image.  It has the same size and shape.  It is simply flipped, rotated, slid...

But... in the fourth, dilation, the image now has a different size.  It is still, however the same shape.

In geometry terms, after the first three transformations, the image is still "congruent" to the pre-image.  After dilation, the image is "similar" but not "congruent."

So... all that to say that when you rotate an angle around the origin, the measure of the angle doesn't change.

So the first choice is correct.  The measure of the image of the angle is the same as the measure of the angle.
<span>m∠X’Y’Z’ = m∠XYZ
</span>
7 0
3 years ago
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Kyona opened a savings account with $500. Her account grew at a rate of 3% per year compounded
Kaylis [27]

Answer:

560.00

Step-by-step explanation:

im really not sure

5 0
3 years ago
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