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2 years ago

You were planning to spend $12 on a

1 answer:

8 0

You have $12, and need at least x more dollars to spend $30 total. So the inequality is 12 + x ≥ 30, where x is the number of dollars needed to get free delivery. To solve for x, subtract 12 from each side of the sign. x ≥ 30 - 12, x ≥ 18. You must spend at least 18 more dollars to qualify for free delivery.

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What is the quotient of -30 and 6? -180 -5 -36 -24

olganol [36]

D I think it's D but if not it's a

8 0

4 years ago

Multiply

brilliants [131]

The answer is going to be y^4 -13y^2 +36
I hope this helps!
Please make me brainiest

3 0

3 years ago

What is (1 2/3) ÷(1/8)

bagirrra123 [75]

1 2/3 = 5/3
Divide fraction, multiply reciprocal
5/3 * 8/1 = 40/3

8 0

3 years ago

Read 2 more answers

A class consists of 23 women and 83 mean. If a student is random selected, what is the probability that the student is a woman?

slavikrds [6]

Answer:

$P(Woman) = \frac{23}{106}$

Step-by-step explanation:

Given

$Women = 23$

$Men = 83$

Required

$P(Woman)$

This is calculated as the number of women divided by the population of the class

i.e.

$P(Woman) = \frac{Women}{Women + Men}$

So, we have:

$P(Woman) = \frac{23}{23+83}$

$P(Woman) = \frac{23}{106}$

7 0

3 years ago

Q20-23 with steps pls

just olya [345]

20: Let $x$ be the amount of money. If this amount is shared between 8 people, each person will get x/8 dollars. But there actually are 6 people, so everyone is getting x/6 dollars. We know that this difference results in 30 dollars more, so we have

$\dfrac{x}{6}=\dfrac{x}{8}+30 \iff \dfrac{x}{6}-\dfrac{x}{8}=30$

Rearrange the left hand side as

$\dfrac{4x-3x}{24}=30$

And multiply both sides by 24 to get

$x=720$

21: Let $M$ and $J$ be the number of marbles owned by Mike and Judy, respectively. At the beginning, we have

$M=3J+11$

If they both get 9 more marbles, Mike will have $M+9$ marbles, and Judy will have $J+9$ marbles. So, we have

$M+J+18=93 \iff M+J=75 \iff M=75-J$

Plug this value in the first equation and we have

$75-J=3J+11 \iff 4J=64 \iff J=16$

And we deduce

$M=16\cdot 3 + 11=59$

So, the difference is

$M-J=59-16=43$

22: Let $x,y,z$ be the number of $10, $20 and $50 coupon, respectively. We're given:

$\begin{cases}x=2y+3\\z=\frac{1}{2}y\\x+y+z=38\end{cases}
We can write the third equation by substituting the expressions for x and z:
[tex]x+y+z=(2y+3)+y+\left(\dfrac{1}{2}y\right)=38$