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Dominik [7]
2 years ago
10

Find the midpoint of (0, 4) and (2, -2)

Mathematics
2 answers:
lidiya [134]2 years ago
5 0

Answer:

\text{Midpoint} = (1, \; 1)

Step-by-step explanation:

M = (x_M, \; y_M)

M = \left(\dfrac{x_1 + x_2}{2}, \; \dfrac{y_1 + y_2}{2}\right)

M = \left(\dfrac{0 + 2}{2}, \; \dfrac{4 + -2}{2}\right)

M = \left(\dfrac{2}{2}, \; \dfrac{2}{2}\right)

M = (1, \; 1)

GaryK [48]2 years ago
4 0

Answer: (1, 1)

Step by Step Explanation:

The midpoint formula is (x + x/2 ,  y + y/2)

If you plug in the coordinates it looks like this

( 0 + 2/2  ,  4 + (-2)/2)

That turns into this:

(2/2  ,  2/2)                              

Which gives you the final answer of (1, 1)          

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3 years ago
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so 33=4x+7x
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3 0
3 years ago
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3 years ago
Write the quadratic equation in general form. (x - 3)^ 2 = 0
algol [13]
The answer is:  x² – 6x + 9 = 0  .
_____________________________________________________
Explanation:
________________________________________________________

Given:  (x – 3)² = 0 ;  write as: general form:  "ax² + bx + c = 0";  a ≠ 0 .
<span>
Note:  </span>(x – 3)² = (x – 3)(x – 3) = x² – 3x – 3x + 9 = x² – 6x + 9 ;
___________________________________________________
Rewrite: (x – 3)²  =  0 ;  →
           as:   x² – 6x + 9 = 0  ; which is our answer.
____________________________________________
→   x² – 6x + 9 = 0  ; is in "general form", or "standard equation format"; that is: " ax² + bx + c = 0 ";  (a ≠ 0) ;
             → in which: 
   a =  1 (implied coefficient, since anything multiplied by "1" is that same                                                                                                                    value);
   b = -6; 
   c =  9
_______________________________________________________
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