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Dominik [7]
2 years ago
10

Find the midpoint of (0, 4) and (2, -2)

Mathematics
2 answers:
lidiya [134]2 years ago
5 0

Answer:

\text{Midpoint} = (1, \; 1)

Step-by-step explanation:

M = (x_M, \; y_M)

M = \left(\dfrac{x_1 + x_2}{2}, \; \dfrac{y_1 + y_2}{2}\right)

M = \left(\dfrac{0 + 2}{2}, \; \dfrac{4 + -2}{2}\right)

M = \left(\dfrac{2}{2}, \; \dfrac{2}{2}\right)

M = (1, \; 1)

GaryK [48]2 years ago
4 0

Answer: (1, 1)

Step by Step Explanation:

The midpoint formula is (x + x/2 ,  y + y/2)

If you plug in the coordinates it looks like this

( 0 + 2/2  ,  4 + (-2)/2)

That turns into this:

(2/2  ,  2/2)                              

Which gives you the final answer of (1, 1)          

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How many 4X4in squares will i need to cover 20ft high 10 ft wide wall
IRINA_888 [86]
Find the area of the squares.
4 ×4 = 16

Find the area of the wall.
20 × 10 =200

Divide 200 by 16.
200 ÷ 16 = 12.5

You need 12.5 squares.
8 0
3 years ago
A large appliance such as a water heater is only running when it has clicked on and is actually heating water. The time your wat
mafiozo [28]

a) Total cost (per day) ≈ $1.40

​b) Total cost (per year) ≈ $510

c) New annual cost = $327

d) The number of years that the water heater pays for itself is; approximately 4 years

<h3>How to calculate Energy Bill?</h3>

Wattage per hour = 4200 Watts per hour

Number of hours per day = 3 hours

Cost per unit = $0.11 per kilowatt-hour

Savings rate = 36%

Cost water heater = $1,100

a) The total wattage is the product of the wattage per hour and the number of hours;

Total wattage (per day) = Wattage per hour × Number of hours

= 4,200 watts per hour × 3 hours

= 12,600 watt-hours

= 12.6 kilowatt-hours

​

The total cost is then the product of the total wattage and the cost per unit:

Total cost (per day) = Total wattage × Cost per unit

Total cost (per day) = 12.6 kilowatt-hours × $0.11 per kilowatt-hour

Total cost (per day) = $1.386

Total cost (per day) ≈ $1.40

​

b) The total cost in a year is the product of the total cost in a day and the number of days in a year. There are 365 days in a year (assuming no leap year).

Total cost (per year) = Total cost (per day) × Number of days in a year

Total cost (per year) = $1.40 × 365

Total cost (per year) = $511

Total cost (per year) ≈ $510

​

c) We are told that this new water heater saves 36% of annual cost. Thus;

Amount saved = 36% * 510 = $183.6

Thus;

New annual cost = $510 - $183 = $327

d) The number of years that the water heater pays for itself is;

1100/327 = 3.36 or approximately 4 years

Read more about Energy Costs at; brainly.com/question/14277272

#SPJ1

6 0
1 year ago
Monique made several batches of soup for a potluck supper. Each batch required 3\4 0f a pound of potatoes, and she used a total
eimsori [14]

Answer:

The\ value\ of\ \frac{6 \frac{1}{2}}{\frac{3}{4}} \ is\ \frac{26}{3}.

The\ value\ of\ \frac{6 \frac{1}{2}}{\frac{3}{4}} \ is\ 8.67 (Approx).

Step-by-step explanation:

As given

Monique\ made\ several\ batches\ of\ soup\ for\ a\ potluck\ supper.

Each\ batch\ required\ \frac{3}{4}\ of\ a\ pound\ of\ potatoes.

she\ used\ a\ total\ of\ 6 \frac{1}{2}\ pounds\ of\ potatoes.

As given the expression.

= \frac{6 \frac{1}{2}}{\frac{3}{4}}

= \frac{\frac{13}{2}}{\frac{3}{4}}

Solving the above

= \frac{13\times 4}{2\times 3}

= \frac{26}{3}

In the decimal form.

= 8.67 (Approx)

Therefore\ the\ value\ of\ \frac{6 \frac{1}{2}}{\frac{3}{4}} \ is\ \frac{26}{3}.

Therefore\ the\ value\ of\ \frac{6 \frac{1}{2}}{\frac{3}{4}} \ is\ 8.67 (Approx).

6 0
3 years ago
X+y=5 3x+3y=10 eliminacion
Dominik [7]



[1] y = -x + 5



3x + 3•(-x +5) = 10

0 = -5 => NO solution
8 0
3 years ago
The consecutive angles of a parallelogram measure (x+30) and 4x°. What is the measure of the smallest
Sophie [7]

Answer:

60

Step-by-step explanation:

180=(x+30)+(4x)

Ok, combine like terms. That'll give you

180=5x+30.

Now solve for x. X is going to equal 30.

Then substitute 30 for x in the angles. One angle will be 60 and the other will be 120.

60 is smaller than 120 so that's your answer.

6 0
3 years ago
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