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leva [86]
3 years ago
15

IF ANYONE KNOWS THIS PLS HELP ASAP

Mathematics
1 answer:
Llana [10]3 years ago
7 0

Answer:good luck

Step-by-step explanation:

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Joshua started cycling at 5:15 pm By 8:09 pm, he has covered a distance of 7250 mWhat was Joshua's average speed during that tim
vivado [14]

The average speed of Joshua during that time is 2500 m/h.

Explanation:

It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.

The total time taken by Joshua from 5:15 pm to 8:09 pm is

2 { h } 54 \text { min }=2 \mathrm{h}+\frac{54}{60} {h}

Dividing we get,

2 { h } 54 \text { min }=2 \mathrm{h}+0.9 {h}

Adding, we have,

2 { h } 54 \text { min }=2.9 {h}

Thus, the total time taken by Joshua is 2.9 {h}

To determine the average speed we use the formula,

speed=\frac{distance}{time}

where distance=7250 and time=2.9

Hence, substituting the values we have,

speed=\frac{7250}{2.9}

Dividing, we get,

speed=2500

Thus, the average speed of Joshua during that time is 2500 m/h.

5 0
3 years ago
...!!.!.!.!.!.!.!.!.!.!.!.!.
Schach [20]

Answer: It is proportional because 195/3 equals 65 and 325/5 equals 65 as well, so it is proportional.

Hope this helps! :)

5 0
3 years ago
Read 2 more answers
If T(x, y) = (x + 5, y + 6) and Pris the image of P, what is the rule for the translation in which P is the image of P'? T(x, y)
xxTIMURxx [149]

Answer:

The translation is;

T(x,y)=(x-5,y-6)

Explanation:

Given the translation rule;

T(x,y)=(x+5,y+6)

when P' is the image of P.

For the inverse, when P is the image of P', the Translation rule would become;

\begin{gathered} x=x^{\prime}+5 \\ x^{\prime}=x-5 \\ y=y^{\prime}+6 \\ y^{\prime}=y-6 \\ So,\text{ the translation rule becomes;} \\ T(x,y)=(x-5,y-6) \end{gathered}

The translation is;

T(x,y)=(x-5,y-6)

3 0
1 year ago
5 1/2+ 3 2/3+ 1 4/5
Mazyrski [523]

Answer:

10\frac{29}{30}

Step-by-step explanation:

5\frac{1}{2} +3\frac{2}{3} +1\frac{4}{5}

Let us group the integers and the fractions.

5\frac{1}{2} +3\frac{2}{3} +1\frac{4}{5} = (5+3+1)+(\frac{1}{2} +\frac{2}{3}+\frac{4}{5}  )

= 9+\frac{15+20+24}{30}

= 9+\frac{59}{30}

=9+1\frac{29}{30}

=10\frac{29}{30}

7 0
4 years ago
1.A house worth $250,000 has an coinsurance clause of 90 percent. The owners insure the property for $191,250. They then have a
Arisa [49]

1. Multiply the value of the house by the percent:

250,000 x 0.9 = 225,000

Divide the amount the owner insured by the clause amount:

191,250/225,000 = 0.85

Multiply that by the amount of damage:

0.85 x 80,000 = 68,000

They will receive $68,000

2. Follow the same steps as above:

180,000 x 0.75 = 135,000

101,250 / 135,000 = 0.75

0.75 x 50,000 = 37,500

They will receive $37,500

8 0
3 years ago
Read 2 more answers
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