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Afina-wow [57]
4 years ago
7

3x-y=3 I need to find x and y​

Mathematics
2 answers:
zubka84 [21]4 years ago
7 0

Answer:

Step-by-step explanation:

I believe X= 2 and Y=3

Anika [276]4 years ago
5 0

well,

3x-y=3

1.x=0

y=-4

2. x=1

y=0

3. x=2

y=3

4.x=3

y=6

5. x=4

y=9

.

.

.

.

m. x=n

y=3(x-1)

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Item 1: sleeved dress $17.99
Oksana_A [137]

Answer:

<em>The final price including tax is $41.89</em>

Step-by-step explanation:

The following items are on sale:

Sleeved dress $17.99

Skirt $16.19

T-shirt $8.99

Subtotal $43.17

The cheapest item is the T-shirt for $8.99 and it will be discounted by 30%:

$8.99 - 30/100 * $8.99 = $8.99 - $2.70 = $6.29

The total sale price is now: $43.17-$2.70=$40.47

Now we add the 3.5% tax:

$40.47 + 3.5/100 * $40.47 = $40.47 + $1.42 = $41.89

The final price including tax is $41.89

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3 years ago
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nevsk [136]
The correct answer is 2
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3 years ago
Solve each equation by completing the square. n^2 - 6n + 6 = -2​
Law Incorporation [45]
<h3><u>Explanation</u></h3>
  • Separate the constant out of expression.

( {n}^{2}  - 6n) + 6 =  - 2

  • Find the constant that makes the expression able to be squared. You have to subtract the separated constant by new constant as well.

( {n}^{2}  - 6n + 9) + 6 - 9 =   - 2 \\  {(n - 3)}^{2}  - 3 =  - 2 \\  {(n - 3)}^{2}  = 1

  • Square Root both sides to get rid the squared expression. Make sure to write plus or minus.

\sqrt{ {(n - 3)}^{2} }  =   + \sqrt{1}  \\   \sqrt{ {(n -  3)}^{2} } =  -  \sqrt{1}  \\ n - 3 = 1 \\ n - 3 =  - 1

n - 3 = 1 \:  \:  \: or \:  \:  \: n - 3  =  - 1 \\ n = 1 + 3 \:  \:  \:  or \:  \:  \: n =  - 1 + 3 \\ n = 4 \:  \:  \: or \:  \:  \: n = 2

<h3><u>Answer</u></h3>

\large \boxed {n = 4,2}

3 0
3 years ago
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