All categories

3 years ago

Find the measure of angle C of a triangle ABC, if: d m∠A = 60°+α, m∠B = 60°−α

Mathematics

2 answers:

Nutka1998 [239]3 years ago

8 0

Answer:

m∠C=60°

Step-by-step explanation:

sukhopar [10]3 years ago

7 0

Answer:

C abc dm<a=60> o+a ,m(b=60o'a is equal to 150

You might be interested in

The diagnosis of a square are a.perpendicular

makkiz [27]

Answer

The correct answer is B

Step-by-step explanation:

It is B because squares don't intersect so it cant be a

They are always congruent and equal so not c or d it has to be B

6 0

3 years ago

Kim drew the diagram below to find x, the length of the pole holding up the stop sign that is at an angle with the ground as sho

Nadya [2.5K]

Answer:

the length of the pole is 9.90 feet.

Step-by-step explanation:

7 0

3 years ago

The radius of a semicircle is 1 kilometer. what is the semicircle's perimeter? use 3.14 for pie.

Aleksandr-060686 [28]

Answer:

5.14 km

Step-by-step explanation:

A semicircle is 1/2 of a circle so the perimeter is just 1/2 of the circumference

C = 2 * pi r for a circle so for a semicircle

1/2* 2* pi *r

pi*r

3.14 * 1

3.14

If we want to include the piece that closes the semicircle, we need to add the diameter

d = 2r = 2(1) = 2

2+3.14 = 5.14

5 0

3 years ago

A lottery has 60 numbers. To win the jackpot one needs to match all 7 numbers that are drawn by the machine. Is this a PERMUTATI

Vadim26 [7]

Answer: Hence, our required probability is $\dfrac{1}{386206920}$

Step-by-step explanation:

Since we have given that

Numbers in a lottery = 60

Numbers to win the jackpot = 7 numbers

We need to find the probability to hit the jackpot:

So, our required probability is given by

$P=\dfrac{^7C_7}{^{60}C_7}\\\\P=\dfrac{1}{386206920}$

This is a combination problem as we need to select 7 numbers irrespective of any arrangements.

Hence, our required probability is [tex]\dfrac{1}{386206920}[/tex

4 0

3 years ago

angel's dad bought a television for her completing all of her digital learning day lesson. he want to warp the gift. the box mea

atroni [7]

Answer: 13 sheets of paper

Step-by-step explanation:

We are given the dimensions of the box and the wrap paper:

Box:

$(56 in)(8 in)(36 in)$

Warp paper:

$(26 in)(17 in)$

Now we need to find the surface area of the box and the area of the wrap paper:

Box:

$surface_{1}=(56 in)(8 in)(2)=896 in^{2}$

$surface_{2}=(8 in)(36 in)(2)=576 in^{2}$

$surface_{3}=(56 in)(36 in)(2)=4032 in^{2}$

$surface-area=896 in^{2}+576 in^{2}+4032 in^{2}=5504 in^{2}$

Warp paper:

$area=(26 in)(17 in)=442 in^{2}$

Dividing the area of the box by the area of the paper:

$\frac{surface-area}{area}=\frac{5504 in^{2}}{442 in^{2}}=12.45 \approx 13$

This means Angel's dad needs to purchase 13 sheets of wrapping paper.

4 0

3 years ago