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saul85 [17]
3 years ago
12

Which answer would be correct

Mathematics
1 answer:
tatuchka [14]3 years ago
5 0
The answer I believe is b

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How many liters of a 20% alcohol solution must be mixed with 60 liters of a 90% solution to get a 80% solution?
leva [86]

x = liters of 20% solution

Mixing the 20% solution with the 60 L of 90% solution gives a new mixture with volume (x + 60) L. Each L of the 20% solution contributes 0.2 L of alcohol and thus a total of 0.2x L of alcohol, while the 60 L of 90% solution contributes 54 L of alcohol.

We want the concentration of the new mixture to be 80%, so we require

\dfrac{0.2x+54}{x+60}=0.8

Solve for x:

0.2x+54=0.8x+42

12=0.4x

\implies\boxed{x=30}

So you will need 30 L of the 20% solution.

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3 years ago
Help me with this math?
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Step-by-step explanation:

6 0
3 years ago
Higher Order Thinking On Friday,
oksian1 [2.3K]

Answer:

The Total number of peoples went to street fair including all three days is 785 peoples .

Step-by-step explanation:

Given as :

The number of people went to fair on Friday = F = 215 peoples

The number of people went to fair on Saturday = Sa = 163 more people than on Friday

So, The number of people went to fair on Saturday = The number of people went to fair on Friday + 163 peoples

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And

The number of people went to fair on Sunday = Su = 192 peoples

So , The Total number of peoples went to fair = The number of people went to fair on Friday + The number of people went to fair on Saturday + The number of people went to fair on Sunday

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∴  The Total number of peoples went to fair = 785 peoples

Hence , The Total number of peoples went to street fair including all three days is 785 peoples . Answer

6 0
3 years ago
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