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3 years ago

If cosVz=0.1673413807, find Vz. Thanks- thold you it was easy.

Mathematics

1 answer:

12345 [234]3 years ago

4 0

Answer:

Vz = arccos(0.1673413807) = 80.37º

Step-by-step explanation:

The inverse function of the cosine is the arc cosine.

That means, that if we have that cos a = 1, a is the angle which has cosine equals 1, so a = arccos(1) = 0º.

In this problem, we have that:

cos(Vz) = 0.1673413807

Vz = arccos(0.1673413807) = 80.37º

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After a thorough research, there exists the same question that have choices.

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4 years ago

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What is the 78th term of the arithmetic sequence -4, -2, 0,

konstantin123 [22]

Answer:

T78=150

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3 years ago

Trevor is analyzing a circle, y2 + x2 = 100, and a linear function g(x). Will they intersect?

lakkis [162]

Given a circle described by the equation:
$y^2+x^2=100$
and a function g(x) given by the table
$\begin{center}
\begin{tabular}{ |c |c |c }
 x & g(x) \\
 -1 & -22 \\
 0 & -20 \\
1 & -18 
\end{tabular}
\end{center}$

The function g(x) describes a straight line with the equation:
$\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1} \\ \\ \frac{y-(-22)}{x-(-1)} = \frac{-20-(-22)}{0-(-1)} \\ \\ \frac{y+22}{x+1} = \frac{-20+22}{0+1} = \frac{2}{1} \\ \\ y+22=2(x+1)=2x+2 \\ \\ y=2x-20$

To check if the circle and the line intersects, we substitute the equation of the line into the equation of the circle to see if we have a real solution.
i.e.
$y^2+x^2=100 \\ \\ (2x-20)^2+x^2=100 \\ \\ 4x^2-80x+400+x^2=100 \\ \\ 5x^2-80x+300=0 \\ \\ x^2-16x+60=0 \\ \\ (x-6)(x-10)=0 \\ \\ x-6=0 \ or \ x-10=0 \\ \\ x=6 \ or \ x=10$

When x = 6, y = 2(6) - 20 = 12 - 20 = -8 and when x = 10, y = 2(10) - 20 = 20 - 20 = 0

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