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Sonja [21]
3 years ago
10

Tina wants to install a square hot tub in her backyard.The backyard is 10feet by 50 feet ,and the hot tub will be 8 feet of the

backyard that will not be covered by the hot tub
Mathematics
1 answer:
Anestetic [448]3 years ago
4 0

Answer:

436 square feet will not be provided for

Step-by-step explanation:

In this question, what we are simply asked to do is to calculate the area of the backyard that would be left after installing a square Hottub.

To get the answer here, what is necessary to do is to subtract the area of the square hot tub from the area of the rectangular yard.

Mathematically, the area of the mathematical yard would be :length * width: the length here is 10 feet and the width is 50 feet.

The area is thus 10 * 50 = 500 square feet

Now, we calculate the area of the square hottub = S^2 where S is the length of the side of the square. In this particular case, S = 8. The area of the square is thus; 8 * 8 = 64 square feet

Now the area left uncovered would now be; 500 sq feet - 64 square feet = 436 square feet

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A bag contains 50 lottery balls, numbered 1-50. A ball is chosen at random, then a month of the year is selected. What is the pr
Morgarella [4.7K]

Answer:

4/75

Step-by-step explanation:

We have two sample spaces

1.Lottery balls

2. Month of the year

For lottery balls the sample space is S= 50

Multiples of 3 between 1 and 50 are

(3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48)= 16 in numbers

Hence the probability of choosing a multiple of 3

Pr(multiple of 3) = 16/50= 8/25

Also the sample space for months of the year is S= 12

Two months starts with letter m, March and may

Pr(of months with m) = 2/12= 1/6

the probability of choosing a multiple of 3 and a month starting with the letter M= 8/25*1/6= 8/150= 4/75

6 0
3 years ago
Identify the x-intercepts of the function below f(x)=x^2+12x+24
damaskus [11]

<u>ANSWER:  </u>

x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

<u>SOLUTION:</u>

Given, f(x)=x^{2}+12 x+24 -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here, for (1) a = 1, b= 12 and c = 24

X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}

\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}

Hence the x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

8 0
3 years ago
Okay so m giving a lot of points so here! (My handwriting is bad lol)
lilavasa [31]

11. >

12. >

14. <

15.<


Hopefully this helps :)

8 0
3 years ago
Read 2 more answers
How many toothpicks would be needed for pattern 4
larisa86 [58]

can you show me what the math problem is?

7 0
3 years ago
I need help with #5 please
Alika [10]

 

Distance from a point to a line (Coordinate Geometry)

Method 1: When the line is vertical or horizontal , the distance from a point to a vertical or horizontal line can be found by the simple difference of coordinates . Finding the distance from a point to a line is easy if the line is vertical or horizontal. We simply find the difference between the appropriate coordinates of the point and the line. In fact, for vertical lines, this is the only way to do it, since the other methods require the slope of the line, which is undefined for evrtical lines.

Method 2: (If you're looking for an equation) Distance = | Px - Lx |

Hope this helps!

4 0
3 years ago
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