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VikaD [51]
3 years ago
5

Find dy/dx by implicit differentiation for the following equation. e^x^2=7x+5y+3

Mathematics
1 answer:
lesantik [10]3 years ago
5 0

Answer:

\displaystyle \frac{dy}{dx} = \frac{2e^{2x} - 7}{5}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Exponential Rule [Powering]: \displaystyle (b^m)^n = b^{m \cdot n}

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative of a constant is 0

Implicit Differentiation

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

eˣ Derivative: \displaystyle \frac{d}{dx}[e^u] = u'e^u

Step-by-step explanation:

<u>Step 1: Define</u>

\displaystyle (e^x)^2 = 7x + 5y + 3

<u>Step 2: Differentiate</u>

  1. Rewrite [Exponential Rule - Powering]:                                                          \displaystyle e^{2x} = 7x + 5y + 3
  2. Implicit Differentiation:                                                                                   \displaystyle \frac{d}{dx}[e^{2x}] = \frac{d}{dx}[7x + 5y + 3]
  3. [Derivative] eˣ derivative:                                                                                \displaystyle 2e^{2x} = \frac{d}{dx}[7x + 5y + 3]
  4. [Derivative] Basic Power Rule:                                                                       \displaystyle 2e^{2x} = 1 \cdot 7x^{1 - 1} + 1 \cdot 5y^{1 - 1}\frac{dy}{dx}
  5. [Derivative] Simplify:                                                                                       \displaystyle 2e^{2x} = 7 + 5\frac{dy}{dx}
  6. [Derivative] [Subtraction Property of Equality] Subtract 7 on both sides:  \displaystyle 2e^{2x} - 7 = 5\frac{dy}{dx}
  7. [Derivative] [Division Property of Equality] Divide 5 on both sides:            \displaystyle \frac{2e^{2x} - 7}{5} = \frac{dy}{dx}
  8. [Derivative] Rewrite:                                                                                       \displaystyle \frac{dy}{dx} = \frac{2e^{2x} - 7}{5}

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives - Implicit Differentiation

Book: College Calculus 10e

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\huge \boxed{\mathfrak{Question} \downarrow}

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\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

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\sf \: f(x) =  {3x}^{2}  + x \\  \\ \sf \: \: Substitute \: x \: as \:  - 5. \\  \\ \sf \:f( - 5) = 3( - 5) ^{2}  + ( - 5) \\ \\  \sf \:Calculate \:  -5 \:  to \:  the \:  power  \: of \:  2 \:  and \:  get \:  25. \\  \\\sf \: 3\times 25+5  \\  \\ \sf \:Multiply \:  3 \:  and \:  25 \:  to \:  get \:  75. \\ \\\sf \:  75+5  \\  \\\sf \:Add \:  75 \:  and \:  5  \: to  \: get  \: 80. \\   \\  =   \boxed{\boxed{ \bf \: 80}}

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