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meriva
3 years ago
11

I'm not sure how to figure this out

Mathematics
1 answer:
Bad White [126]3 years ago
6 0

9514 1404 393

Answer:

  10°, 80°

Step-by-step explanation:

<em><u>Setup</u></em>

Let x and y represent the measures of the two acute angles in the right triangle.

From your knowledge of right triangles, you know the two acute angles are complementary:

  x + y = 90

The problem statement gives you another relation:

  x = 2(y + 30) . . . . twice the sum ...

__

<em><u>Solution</u></em>

The second equation gives you an expression for x that can be substituted into the first equation.

  (2(y +30)) + y = 90

  3y +60 = 90 . . . . . . . . collect terms

  3y = 30 . . . . . . . . . subtract 60

  y = 10 . . . . . . . . divide by 3

  x = 2(y +30) = 2(40) = 80

The two angles are 10° and 80°.

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Please help with #6 need it very soon
gregori [183]

Answer:

If this is a proof then here is the answer.

Angle ABD is Congruent to Angle CBD = Given

Angle BDA is Congruent to Angle BDC = Given

Angle ABD is Congruent to Angle CBD = Definition of Angle Bisector

Line Segment BD is Congruent to Line Segment BD = Reflexive Property

Line Segment AB is Congruent to Linge Segment CB = Angle-Side-Angle or ASA

Step-by-step explanation:

Lucky for you, I just learned this also ;)


Since you are given your first two directions, put them down as GIVEN in the proof.

Next, Since ABD and CBD are congruent angles, you can assume that it is an angle bisector since angle bisectors always bisect equally.

Then, (This one is obvious), since Line Segment BD shares a side with itself, it is equal by the Reflexive Property (EX: AB is congruent to AB).

Finally, Since there is two angles with a congruent side in the middle, you can confirm that it is equal by Angle-Side-Angle.

Hope this helped!


5 0
3 years ago
Help with all please
seropon [69]

a) First, draw a graph. The x axis should be numbered: 0, 1, 2, 3, 4, 5, 6, 7, 8. Each number is the last digit of the year. For each year, there is one average score that has to be plotted. Number the y axis of the graph from 0-600, by increments of 50, or something around there. Now, with each year (each x value) place the dot as high as the average score. Repeat with all years. DO NOT draw a line to connect them. A scatter plot is a bunch of points that are not connected.

b) Use the form (y2-y1)/(x2-x1) where (x1,y1) (x2,y2) are any two points from 2001-2006. It does not matter which points, pick any, and assign each of the numbers x1,y1 and x2,y2. Plug it in to the equation, and simplify. This is your slope, also called m. Now plug m into the equation y-y1=m(x-x1) where y1 and x1 are the x and y coordinates of any point from 2001 to 2006. x and y dont have values themselves, they stay there. Now distribute the m into the parenthesis, add y1 to both sides (to cancel it out on the left), and you should be left with the same equation, but now in y=mx+b form. B is where the line crosses the y axis, so put a point on the vertical axis where b is. M is your slope, so every time you go to the right one number, go up M numbers. Draw another point. Repeat this until you can connect these new dots into a line. This line should be on the same graph as your other points, but might not touch all of the scatter plot points. That's still okay, just leave it as is.

c) Find the point where x=6 (meaning the year is 2006) on your line. Find the average test score for that year by seeing where the point lines up along the y axis (draw a straight line from the point to the left to see, if you have to). Take that number and add 1m (the m is the number you used in step B) to it. This predicts what the average score might be after 1 (that's why the 1 is there) year. This is a predicted value, and might not be perfectly correct!! Write/record how close this new, predicted, score is to the actual number, 515, which can be found on the scatter plot.

d) repeat step C exactly as before (still use the year 2006) , but add 4m instead of 1m, to get the predicted score 4 years after 2006 (2010), instead of 1 year after (2007).

I hope I have been of some help! Best of luck!!! :)

3 0
3 years ago
Elle decreased her monthly budget from $250 to $200. Calculate the percent decrease
kirill [66]
Formula for finding percent change (increase or decrease) is amount of the change divided by the original amount.

Here, the amount of the change is 50 and the original amount is 250.

50/250= 0.2

Multiply by 100 to get percent.

20% decrease (because budget went down)
6 0
3 years ago
Simplify foundation of alegebra
Eva8 [605]

1.) -8 + 10(6 + 4r)

First multiply the 10 into (6 + 4r)

-8 + 60 + 40r

52 + 40r


2.) (8m² - 8m + 8) - (2m - 7m² - 6)

Distribute the - into (2m - 7m² - 6)

8m² - 8m + 8 - 2m + 7m² + 6

Combine like terms

15m² - 10m + 14

(idk if you need to factor this or if you can leave it as is)

3 0
4 years ago
A sports magazine conducted a survey to find out the size of the viewership for three different sports in a state. The survey wa
ratelena [41]

Answer:

C

Step-by-step explanation:

This was a bias, because in the location, there must have been a greater concentration of basketball fans than fans of any other sport.

Hope this helped.

3 0
4 years ago
Read 2 more answers
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