A standard numbered cube (die) has six faves numbered 1, 2, 3, 4, 5, 6
Three are even 2, 4, 6 and three are odd 1, 3, 5
P(even) = 3/6
P(odd) = 3/6
So for a fair die an odd number is equally likely as an even number
Answer:
C: .75
Step-by-step explanation:
I really just subtracted
Answer:2x-5y=17;6x-5y=-9
Step-by-step explanation:
Solve equation [2] for the variable x
[2] 6x = 5y - 9
[2] x = 5y/6 - 3/2
// Plug this in for variable x in equation [1]
[1] 2•(5y/6-3/2) - 5y = 17
[1] - 10y/3 = 20
[1] - 10y = 60
// Solve equation [1] for the variable y
[1] 10y = - 60
[1] y = - 6
// By now we know this much :
x = 5y/6-3/2
y = -6
// Use the y value to solve for x
x = (5/6)(-6)-3/2 = -13/2
80.51275. Because 1 pound=0.453592 kilograms. 0.453592*71=32.2051 32.2051*2.5=80.51275