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makvit [3.9K]
2 years ago
8

Help please!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
DedPeter [7]2 years ago
6 0

Answer:

3/4

Step-by-step explanation:

We want to find the probability that a student has a dog given that they have a cat, this means that the information given from the side that says " does not have a cat " is irrelevant and we only look at the information from the side that says " has a cat "

Probability = favorable outcomes / total # of outcomes

Favorable outcomes = Having a cat and dog , 6 students have both a cat and dog so favorable outcomes = 6

Total # of outcomes = total # of students that have a cat whether they have a dog or not. Total # of tudents that have a cat = 6 + 2 = 8

So probability of having a dog given that they have a cat = 6/8 or 3/4

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Find a point on the y-axis that is equidistant from the points (8, −8) and (1, 1).
artcher [175]

\text{We know that any point on the y-axis is of the form (0, y),}\\
\text{because on y-axis we have x=0.}\\
\\
\text{So let (0, y) be the point on the y-axis that is equidistance from}\\
\text{the points }(8,-8) \text{ and }(1,1)\\
\\
\text{so using the distance formula, we have}\\
\\
\text{Distance between (0, y) and }(8,-8)=\text{Distance between (0,y) and }(1,1)\\
\\
\Rightarrow \sqrt{(0-8)^2+(y-(-8))^2}=\sqrt{(0-1)^2+(y-1)^2}

\Rightarrow \sqrt{64+(y+8)^2}=\sqrt{1+(y-1)^2}\\
\\
\text{Squaring both sides, we get}\\
\\
(\sqrt{64+(y+8)^2})^2=(\sqrt{1+(y-1)^2})^2\\
\\
\Rightarrow 64+(y+8)^2=1+(y-1)^2\\
\\
\Rightarrow 64+(y^2+16y+64)=1+(y^2-2y+1)\\
\\
\Rightarrow y^2+16y+128=y^2-2y+2\\
\\
\Rightarrow y^2+16y-y^2+2y=2-128\\
\\
\Rightarrow 18y=-126\\
\\
\Rightarrow y=\frac{-126}{18}\\
\\
\Rightarrow y=-7

So the point on the y-axis that is equidistant from the points (8,-8) and (1,1) is: (0,-7)

3 0
4 years ago
-5x-3y=22 help plz ​
Lerok [7]

Answer:

<h2>(-2, -4)</h2>

Step-by-step explanation:

Put the coordinates of the points to the equation, and check it:

(-4, -1) → x= -4, y = -1

L = -5(-4) - 3(-1) =20 + 3 = 23

R = 22

L ≠ R

(-1, -4) → x= -1, y = -4

L = -5(-1) - 3(-4) = 5 + 12 = 17

R = 22

L ≠ R

(-2, -4) → x= -2, y = -4

L = -5(-2) - 3(-4) = 10 + 12 = 22

R = 22

L = R    CORRECT :)

(-4, -2) → x = -4, y = -2

L = -5(-4) - 3(-2) = 20 + 6 = 26

R = 22

L ≠ R

3 0
3 years ago
9
rjkz [21]
15, Yes: a^2 +b^2 = c^2
9^2+12^2= 225
The square root of 225 is 15, therefore x=15.
Answer to question is yes.
3 0
3 years ago
Read 2 more answers
Which representation has a constant of variation of –2.5? A x –2 –3 –4 –5 y –5 –7.5 –10 –12.5 B 5 x + 2 y = 0 C y = negative 2.5
artcher [175]

Answer:

1

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the roots of the equation f(x) = x3 - 0.2589x2 + 0.02262x -0.001122 = 0
motikmotik

Answer:

x1 = 0.16203454

x2= 0.04843273+0.06766624j

x3= 0.04843273-0.06766624j

Step-by-step explanation:

The better way to obtain roots of a polynomial when is not easy to analytically factorize is to use software as Matlab or Python. Use the following code in Python

import numpy as np

pol=np.array([1,-0.2589, 0.02262,-0.001122])

roots=np.roots(pol)

print(roots)

3 0
3 years ago
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