How do you compare 4/15 and 3/4?

1 answer:

6 0

Find the least common denominator or LCM of the two denominators. LCM of 4 and 15 is 60. 4x15= 60 34=3x154x15=4560 3/4 is bigger

You might be interested in

How do you simplify: <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%28125%20%5E%7B2%7D%20%7D%20%29%20%20%20%5E%7B%20-%20

Nady [450]

Answer:

$\huge\boxed{\sqrt{(125^2)^{-\frac{1}{3}}}=\dfrac{1}{5}}$

Step-by-step explanation:

$\sqrt{(125^2)^{-\frac{1}{3}}}\qquad\text{use}\ (a^n)^m=(a^m)^n\\\\=\sqrt{\left(125^{-\frac{1}{3}\right)^2}\qquad\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=125^{-\frac{1}{3}}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=\dfrac{1}{125^\frac{1}{3}}\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\=\dfrac{1}{\sqrt[3]{125}}=\dfrac{1}{5}\qquad\text{because}\ 5^3=125$

5 0

3 years ago

Need help with this math

zhannawk [14.2K]

The answer for it would be 114t/v

4 0

3 years ago

If zeba were younger by 5 years than what she really is then the square of her age would have been 11 more than five times her a

RSB [31]

Answer:

14 years old

Step-by-step explanation:

Define the variable

Let x be the actual age of Zeba (in years).

Create an equation using the give information and the variable x:

$(x - 5)^2=5x+11$

To find Zeba's age now, solve the equation for x.

Expand the brackets:

$\implies x^2-10x+25=5x+11$

Subtract 5x from both sides:

$\implies x^2-10x+25-5x=5x+11-5x$

$\implies x^2-15x+25=11$

Subtract 11 from both sides:

$\implies x^2-15x+25-11=11-11$

$\implies x^2-15x+14=0$

Factor the found quadratic

To factor a quadratic in the form $ax^2+bx+c$ , find two numbers that multiply to $ac$ and sum to $b$ , then rewrite $b$ as the sum of these two numbers: