The first one is A and then the next one I believe should be 210 for both
Csc x · sec x - tan x =
= 1 / sin x · 1 / cos x - sin x / cos x =
= 1 / sinx cos x - sin² x / sin x cos x =
= ( 1 - sin² x ) / (sin x cos x) =
= cos² x / ( sin x cos x ) =
= cos x / sin x = cot x
Answer:
(1,0)
Step-by-step explanation:
we can't factor this so we'll use the quadratic formula

(use both of them because usually there are two zeroes)
We have

Therefore the x intercept is just (1,0)
Step-by-step explanation:
as in the other problem, the table describes mutually exclusive attributes.
so, we can simply sum the numbers up to get the total number of students :
3+9+2+16 = 30 students.
so, when picking a random student, we have 30 possibilities.
now, how many of those 30 have the desired attributes (to have a brother AND a sister) ?
I see 3 in the table.
so, the probability to pick a student that has a brother and a sister is
3/30 = 1/10 = 0.1
Primeiro multiplica o -2 com tudo que tem dentro do parenteses (chuveirinho) -114 = -5x -2(4x+18)
-2 . 4x = -8x + -2 . 18 = -36 = -8x-36
Agora soma os números com incógnitas (no caso x)
-114 = - 5x - 8x -36
Joga a incógnita do outro, tornando positiva
-114 = -13x - 36
13x -114 = -36
e o 114 do outro lado, ficando positiva também
13x -114 = -36
13x = - 36 + 114
13x = 78
x = 78 /13
x= 6
ESPERO TER AJUDADO :)