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Romashka [77]
3 years ago
13

A. (3,-2) B. (2,3) C. (4,1) D. (-1,4)

Mathematics
1 answer:
lana66690 [7]3 years ago
3 0
The answer is b (2,3)
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Solve for x. Round to the nearest hundredth if necessary.
I am Lyosha [343]

Answer:

Step-by-step explanation:

\frac{19}{x} = tan 29°

x = \frac{19}{tan29^o} ≈ 34.28

4 0
2 years ago
How much would it cost to buy a piece of candy for 50 cents plus tax
gtnhenbr [62]

Answer:

it depends on which state your in or in your even in the us usually it is either 6% or 4% some times more or less % so im going to do both

50*0.06=53

50*0.04=52

Hope This Helps!!!

5 0
2 years ago
The dinner bill came to $24.29 before tax and tip. If the taxes were 6% and they decided to leave an 18% tip, what was the total
olga_2 [115]

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$30.64 +6% tax and 18% tip

Step-by-step explanation:

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3 years ago
3(x+5)= 30 divided by 5
harina [27]

Answer:

x=-3

Step-by-step explanation:

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3 0
3 years ago
According to the National Vital Statistics, full-term babies' birth weights are Normally distributed with a mean of 7.5 pounds a
Sav [38]

Answer:

68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 7.5, \sigma = 1.1

What is the probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

This is the pvalue of Z when X = 8.6 subtracted by the pvalue of Z when X = 6.4. So

X = 8.6

Z = \frac{X - \mu}{\sigma}

Z = \frac{8.6 - 7.5}{1.1}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 6.4

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.4 - 7.5}{1.1}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

6 0
3 years ago
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