Answer:
Hence, the relation R is a reflexive, symmetric and transitive relation.
Given :
A be the set of all lines in the plane and R is a relation on set A.
To find :
Which type of relation R on set A.
Explanation :
A relation R on a set A is called reflexive relation if every 
then 
.
So, the relation R is a reflexive relation because a line always parallels to itself.
A relation R on a set A is called Symmetric relation if 
then 
for all 
.
So, the relation R is a symmetric relation because if a line 
is parallel to the line 
the always the line is parallel to the line .
A relation R on a set A is called transitive relation if and 
then 
for all 
.
So, the relation R is a transitive relation because if a line s parallel to the line and the line is parallel to the line 
then the always line is parallel to the line .
Therefore the relation R is a reflexive, symmetric and transitive relation.
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Answer:
equation;
Center (-4,2)
Radius is
Step-by-step explanation:
Since the x^2 and y^2 have the same coeffiecent this will be a circle in a form of
Where (h,k) is center
r is the radius
So first we group like Terms together
Add 7 to both sides
Since the orginal form of the equation of the circle has a perfect square we need to complete the square for each problem
and
so we have
To find our center, h is -4 and k is 2
so the center is (-4,2)
The radius is
So the radius is 3 times sqr root of 3.
Im assuming by 5-.8, you mean 5/8ths and by 1-.4, you mean 1/4th...
x=5/8+1/4
x=5/8+2/8
x=7/8
They ate 7/8 together
The answer is choice B
y > (2/3)x + 1
The boundary line is the equation y = (2/3)x + 1 which can be found through the slope formula to get m = 2/3. Then you use one of the two points on the line to find b = 1.
The equal sign in y = (2/3)x + 1 changes to a "greater than" sign to indicate two things
A) The shaded region is above the boundary line
B) The boundary line itself is a dashed line to indicate "no solution points on this line"
