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Alekssandra [29.7K]
3 years ago
5

Analyze the diagram below and complete the instructions that follow.

Mathematics
1 answer:
MAXImum [283]3 years ago
8 0

Answer:

XAW = 3(23) = 69 degrees.

WAY = 23 + 88 = 111 degrees.

ZAY = 8(12) - 23 = 73 degrees.

XAZ = 6(12) + 35 = 107 degrees.

Step-by-step explanation:

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Can some help me with this question
Luden [163]

To find the equation of this line in slope-intercept form (y = mx + b, where m is its slope and b is its y-intercept), we naturally need the slope and the y-intercept. We can see that the line intersects the y-axis at the point (0, 4) so our y-intercept is 4, and the line rises 4 along the y-axis for every 2 it runs along the x-axis, so its slope is 4/2 = 2. With this in mind, we can write the line's equation as

y = 2x + 4

7 0
3 years ago
Plz help me 8+x^2-11
likoan [24]

Answer:

-3 + x^2

Step-by-step explanation:

8+x^2-11

First combine the like terms.

so..

8-11 = -3

= -3 + x^2

but we don't know the value of x so we just leave it as it is.

And they both are not like terms so we cant solve them together so you stop there

Hope that helped!

6 0
3 years ago
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How do you do this??????
slava [35]

Answer:

2:1

Step-by-step explanation:

There are 14 spoons (not sure what they are) and 7 eyes so it is 14:7

simplified it is 2:1

Hope this helps :)

4 0
3 years ago
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A sample of 81 account balances of a credit company showed an average balance of $1,200 with a standard deviation of $126.
TEA [102]

Answer:

(a) Null Hypothesis, H_0 : \mu = $1,150  

    Alternate Hypothesis, H_A : \mu \neq $1,150

(b) The test statistic is 3.571.

(c) We conclude that the mean of all account balances is significantly different from $1,150.

Step-by-step explanation:

We are given that a sample of 81 account balances of a credit company showed an average balance of $1,200 with a standard deviation of $126.

We have test the hypothesis to determine whether the mean of all account balances is significantly different from $1,150.

<u><em>Let </em></u>\mu<u><em> = mean of all account balances</em></u>

(a)So, Null Hypothesis, H_0 : \mu = $1,150     {means that the mean of all account balances is equal to $1,150}

Alternate Hypothesis, H_A : \mu \neq $1,150    {means that the mean of all account balances is significantly different from $1,150}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about population standard deviation;

                               T.S.  = \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average balance = $1,200

             s = sample standard deviation = $126

             n = sample of account balances = 81

(b) So, <u>test statistics</u>  =  \frac{1,200-1,150}{\frac{126}{\sqrt{81} } }  ~ t_8_0

                               =  3.571

The value of the sample test statistics is 3.571.

(c) <u>Now, P-value of the test statistics is given by the following formula;</u>

          P-value = P( t_8_0 > 3.571) = <u>Less than 0.05%</u>

Because in the t table the highest critical value for t at 80 degree of freedom is given between 3.460 and 3.373 at 0.05% level.

Now, since P-value is less than the level of significance as 5% > 0.05%, so we sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean of all account balances is significantly different from $1,150.

8 0
3 years ago
What expression is equivalent to -3z-z
NeX [460]

Answer:

-4z

Step-by-step explanation:

4 0
3 years ago
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