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mestny [16]
3 years ago
10

There are 10 mangoes inside the basket. Each mango weighs 50grams.Approximately, what is the weight the basket if the basket wit

h the mangoes inside of it weighs 600gram?
Mathematics
1 answer:
deff fn [24]3 years ago
4 0

Answer:

100 grams.

Step-by-step explanation:

600-(10*50). You're subtracting the weight of 10 mangoes (50 grams for each mango) from 600 grams, which will give you the weight of the basket.

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Mr. O'Connor had $90 to spend at a football game. He spent 31/45 on his ticket. Then, he spent 3/7 of his remaining money at the
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He has $90 in total to spend

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so money spent on ticket =(31/45) *90 =2790/45 =62

Now money left with him is 90-62 =28 $

Now it says that he spent (3/7) of this remaining money at concession stand

so money spent on concession stand =(3/7)*28 =84/7 =12

Now money left with him = 28-12 =16

So money left with him is $16 but hat costs for $18

So Mr. O'Connor didnt have enough moeny to buy the hat

4 0
3 years ago
If f(x) = 5x + 4, which of the following is the inverse of Ax)?
Levart [38]

Answer:

f^{-1} (x) = \frac{x-4}{5}

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

y = 5x + 4 ( subtract 4 from both sides )

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change x to f^{-1}(x) and y back to x, thus

f^{-1}(x) = \frac{x-4}{5}

6 0
3 years ago
Dinosaur fossils are often dated by using an element other than carbon, like potassium-40, that has a longer half life (in this
Firlakuza [10]
The amount of substance left of a radioactive element of half life, t_{\frac{1}{2}} after a time, t, is given by:

N(t)=N_0\left( \frac{1}{2} \right)^ \frac{t}{t_{  \frac{1}{2} }}

Given that <span>potassium-40 has a half life of approximately 1.25 billion years.

The number of years it will take for 0.1% of potassium-40 to remain is obtained as follows:

0.1=100\left( \frac{1}{2} \right)^ \frac{t}{1.25}} \\  \\ \Rightarrow\left( \frac{1}{2} \right)^ \frac{t}{1.25}}=0.001 \\  \\ \Rightarrow\frac{t}{1.25}\ln\left( \frac{1}{2} \right)=\ln(0.001) \\  \\ \Rightarrow \frac{t}{1.25}= \frac{\ln(0.001)}{\ln\left( \frac{1}{2} \right)} =9.966 \\  \\ t=9.966(1.25)=12.5

Therefore, </span><span>the maximum age of a fossil that we could date using 40k is 12.5 billion years.</span>
3 0
3 years ago
What would the extrema be for z = f(x,y) = (y^2)-(x^2)?
lubasha [3.4K]

Answer:

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Step-by-step explanation:

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