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s2008m [1.1K]
3 years ago
11

Write an equation of the line that passes through the point (2, 3) and is perpendicular to the line y = 1/2x - 1

Mathematics
1 answer:
RoseWind [281]3 years ago
6 0
Perpendicular means opposite and reciprocal (in reference to the slope). 
The opposite of 1/2 is -1/2. The reciprocal of -1/2 is -2.

Now we know the slope we can plug the point they gave us into the X and Y positions to solve for b (in the point (2, 3) there is a X - Value (2) and a Y-value (3)

y= -2x+b
3= -2(2)+b
3= -4+b
1=b

Now we plug b and the slope in the generic y=mx+b equation:
y= -2x+1
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Answer:

g(x) = \frac{1}{3}(x - 1) = \frac{x}{3} - \frac{1}{3}

Step-by-step explanation:

f(x) = 3x + 5

f[g(x)] = 3[g(x)] + 5

⇒  3[g(x)] + 5 = x + 4

⇒  3[g(x)] = x + 4 - 5

⇒  3[g(x)] = x - 1

⇒  g(x) = \frac{1}{3}(x - 1) = \frac{x}{3} - \frac{1}{3}

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Solve the following system of linear equations: 3x1+6x2+6x3 = -9 -2x1–3x2-3x3 = 3 If the system has infinitely many solutions, y
choli [55]

Answer:

The set of solutions is \{\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}12\\-7-r\\r\end{array}\right]: \text{r is a real number}  \}

Step-by-step explanation:

The augmented matrix of the system is \left[\begin{array}{ccccc}3&6&6&-9\\-2&-3&-3&3\end{array}\right].

We will use rows operations for find the echelon form of the matrix.

  • In row 2 we subtract \frac{2}{3} from row 1. (R2- 2/3R1) and we obtain the matrix \left[\begin{array}{cccc}3&6&6&-9\\0&1&1&-7\end{array}\right]
  • We multiply the row 1 by \frac{1}{3}.

Now we solve for the unknown variables:

  • x_2+x_3=-7, x_2=-7-x_3
  • x_1+2x_2+2x_3=-2, x_1+2(-7-x_3)+2x_3=-2 then x_1=12

The system has a free variable, the the system has infinite solutions and the set of solutions is \{\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}12\\-7-r\\r\end{array}\right]: \text{r is a real number}  \}

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