4 years ago

The quotient of 11 and the difference of 13 and a number

Mathematics

1 answer:

vesna_86 [32]4 years ago

7 0

Answer:

( 13 - x ) / 11

~Hope this helps

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A principal of $4200 is invested at 9% Interest, compounded annually. How much will the investment worth after 6 years? Use the

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Answer:7043.82

It would be 4200 x 1.09 which is the interest to the power of 6 for the number of years which would then give you 4200 x 1.09^6. This will then give the answer of 7043.82

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3 years ago

Which ones are the alternative exterior angles

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Step-by-step explanation:

Angle pair 1 and 8

and

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3 years ago

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If you want to be 95% confident of estimating the population mean to within a sampling error of plus or minus3 and the standard

Aleksandr [31]

Answer:

The sample size required is at least 171

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

What sample size is required?

A samle size of at least n is required, in which n is found when $M = 3, \sigma = 20$

$M = z*\frac{\sigma}{\sqrt{n}}$

$3 = 1.96*\frac{20}{\sqrt{n}}$

$3\sqrt{n} = 20*1.96$

$\sqrt{n} = \frac{20*1.96}{3}$

$(\sqrt{n})^{2} = (\frac{20*1.96}{3})^{2}$

$n = 170.7$

Rouding up

The sample size required is at least 171

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3 years ago

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Mean, median, range, m.a.d.

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3 years ago

Alison, Hector, and Myles had a challenge to see who could run the farthest in a month. Alison ran 21 miles. Hector ran 5 times

Leno4ka [110]

Myles ran 2 times what alison ran:
2x21 = 42

Hector ran 5 times as many miles as Myles:
42x5 = 210

therefore Hector ran 210 miles.

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3 years ago