The complete question in the attached figure
we have that
tan a=7/24 a----> III quadrant
cos b=-12/13 b----> II quadrant
sin (a+b)=?
we know that
sin(a + b) = sin(a)cos(b) + cos(a)sin(b<span>)
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step 1
find sin b
sin²b+cos²b=1------> sin²b=1-cos²b----> 1-(144/169)---> 25/169
sin b=5/13------> is positive because b belong to the II quadrant
step 2
Find sin a and cos a
tan a=7/24
tan a=sin a /cos a-------> sin a=tan a*cos a-----> sin a=(7/24)*cos a
sin a=(7/24)*cos a------> sin²a=(49/576)*cos²a-----> equation 1
sin²a=1-cos²a------> equation 2
equals 1 and 2
(49/576)*cos²a=1-cos²a---> cos²a*[1+(49/576)]=1----> cos²a*[625/576]=1
cos²a=576/625------> cos a=-24/25----> is negative because a belong to III quadrant
cos a=-24/25
sin²a=1-cos²a-----> 1-(576/625)----> sin²a=49/625
sin a=-7/25-----> is negative because a belong to III quadrant
step 3
find sin (a+b)
sin(a + b) = sin(a)cos(b) + cos(a)sin(b)
sin a=-7/25
cos a=-24/25
sin b=5/13
cos b=-12/13
so
sin (a+b)=[-7/25]*[-12/13]+[-24/25]*[5/13]----> [84/325]+[-120/325]
sin (a+b)=-36/325
the answer issin (a+b)=-36/325
Answer:
$150.
Step-by-step explanation:
You would add to get the answer.
57 + 90 = 150.
Feel free to let me know if you need more help. :)
So from the previous question which was (
brainly.com/question/928111) he cut the pie into 8 pieces
so he ate 1 and 2
1+2=3
he ate 3
8 pieces-3=5
fractin not eate is 5/8
If the y-coordinates of the given vertices and foci are the same, then the major axis is parallel to the x-axis. Use the standard form (x−h)2a2+(y−k)2b2=1 ( x − h ) 2 a 2 + ( y − k ) 2 b 2 = 1 . If the x-coordinates of the given vertices and foci are the same, then the major axis is parallel to the y-axis.
Hope I helped you! :)
Below is a drawing I did!
Answer:
x= 7
x=6
Step-by-step explanation:
5+2x=19
Subtract 5 from both sides
so...
2x=14
then divide by two to isolate the x
so..
x=7
4x+3=27
Subtract 3 from both sides
so...
4x=24
then divide by 4 to isolate the x
so....
x=6