D(t)=-16t²+32t+88
a] Maximum height
At maximum height d'(t)=0
from d(t);
d'(t)=-32t+32=0
thus
t=1
hence the maximum height will be:
d(t)=-16t²+32t+88
d(1)=-16(1)^2+32(1)+88
d(1)=104 ft
2] <span> how many seconds does it take to reach the ground after first being thrown upward?
Here we solve for t intercept
</span>when d(t)=0
<span>thus</span>
0=-16t²+32t+88
<span>solving for t, we get:
t=1-</span>√13/2
or
<span>t=1+</span>√13/2
<span>
t=-1.55 or t=3.55 sec
Thus the answer is t=3.55 sec
</span>
Answer:
i think x its 8
Step-by-step explanation:
Find the vertex by using the formula -b/2a
To find a and b, we must know that a and b are located at y = ax^2 + bx + c.
We find that b is 4 and a is 1 by looking at the given quadratic function.
The answer is A. -4/2(1) because the question is looking for the correct steps to find the answer.
Answer:
the complete graph is in the image
Step-by-step explanation:
to plot this, plug in values of x and find y.
The angle of WVZ is (2a + 6)°.
