Answer:
The answer is "15 minutes"
Explanation:
I will approximately spend 15 minutes on prewriting once i have gathered the information needed.
Answer: True
Explanation:
Decision regarding an asset replacement is usually based on both the internal rate of return and the net present value of the incremental cash flows.
Therefore, it should be noted that this brings about the complications when comparing the development of relevant cash flows to the expansion decisions.
Answer:
The Treynor index for the stock will be 0.02.
Explanation:
The average return of the stock is 10%.
The average risk-free rate is 7%.
The standard deviation of the stock's return is 4%.
Stock's beta is given at 1.5.
Treynor index
= (Portfolio return- risk free return)/beta of the portfolio
=(0.10-0.07)/1.5
=0.03/1.5
=0.02
So, the Treynor index for the stock will be 0.02.
Answer:
Price to be paid now = $52.89
Explanation:
<em>The Dividend Valuation Model is a technique used to value the worth of an asset. According to this model, the worth of an asset is the sum of the present values of its future cash flows discounted at the required rate of return. </em>
T<em>he stock would be held for just a period, hence we would use the single period return model. This is given as follows:</em>
Price now = D/(1+r) + P×(1+r)
Dividend , r - rate of return, P -year-end price of stock
Dividend = 4.35, r-16%, P- 57
Price = 4.35/(1.16) + 57/(1.16)= $52.89
Price to be paid now = $52.89
Answer:
A) interest rate
Explanation:
Interest rate risk refers to the risk of purchasing a bond that offers a certain coupon and then the price of that bond changes due to changes in the market interest rate.
This can work in your favor, if the market interest rate decreases, you will have a bond that pays above market coupon, which will increase the market value of the bond. But if the market interest rate increases, the market value of your bond will decrease, and you will lose money. This is what happened to Albert, since the market interest rate increased, the value of Albert's bond decreased.