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Inessa [10]
3 years ago
15

Is a term used to define those providers or hospitals that have the capabilities and processes in place to be actively use certi

fied electronic health record technology?
Computers and Technology
1 answer:
aksik [14]3 years ago
5 0
Meaningful use (MU) i<span>s a term used to define those providers or hospitals that have the capabilities and processes in place to be actively use certified electronic health record technology.
</span><span>This term is used in a health information technology (HIT) context.
</span><span> It defines minimum U.S. government standards for </span>using<span> electronic health records (EHR) and for exchanging patient clinical data between healthcare providers.</span>
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E gpa(grade point average) you need to have or you get kicked out of robotics for middle school?
velikii [3]
Every school is different.  Some you have to keep above a C average.  Others you only have to be passing.  You will have to check your student handbook.
3 0
2 years ago
Which of the following does not make a good analysis class? (Points : 6) its name reflects its intent
satela [25.4K]

Answer:it has high coupling

Explanation: Coupling is the property in the field of computer program that is defined as the functions ,data and  codes of the program are dependent on each other and cannot be changed independently if requires. Thus,high amount of coupling is not considered as good factor due to high interdependence. Loose coupling can be still permitted.

Other options are correct because name of the class should reflect the purpose and well defined responsibilities should be present, modeling of certain component and high cohesion means keeping similar functions togather is also required. So, the only bad factor is high coupling

6 0
3 years ago
Assume a TCP sender is continuously sending 1,090-byte segments. If a TCP receiver advertises a window size of 5,718 bytes, and
Arturiano [62]

Answer:

for the 5 segments, the utilization is 3.8%

Explanation:

Given the data in the question;

segment size = 1090 bytes

Receiver window size = 5,718 bytes

Link transmission rate or Bandwidth = 26 Mbps = 26 × 10⁶ bps

propagation delay = 22.1 ms

so,

Round trip time = 2 × propagation delay = 2 × 22.1 ms = 44.2 ms

we determine the total segments;

Total segments = Receiver window size / sender segment or segment size

we substitute

Total segments = 5718 bytes / 1090 bytes

Total segments = 5.24587 ≈ 5

Next is the throughput

Throughput = Segment / Round trip

Throughput = 1090 bytes / 44.2 ms

1byte = 8 bits and 1ms = 10⁻³ s

Throughput = ( 1090 × 8 )bits / ( 44.2 × 10⁻³ )s

Throughput = 8720 bits / ( 44.2 × 10⁻³ s )

Throughput = 197.285 × 10³ bps

Now Utilization will be;

Utilization = Throughput / Bandwidth

we substitute

Utilization = ( 197.285 × 10³ bps ) / ( 26 × 10⁶ bps )

Utilization = 0.0076

Utilization is percentage will be ( 0.0076 × 100)% = 0.76%

∴ Over all utilization for the 5 segments will be;

⇒ 5 × 0.76% = 3.8%

Therefore, for the 5 segments, the utilization is 3.8%

4 0
3 years ago
You are most likely to use<br> images for photos or digital paintings.
Lubov Fominskaja [6]

Answer: Digital Paintings

7 0
3 years ago
what types of physical drives does windows disable defragmenting, but provides another method of optimization?
Anika [276]

The type of physical drives does windows disable defragmenting, but provides another method of optimization is known as windows.

<h3>What is windows?</h3>

It should be noted that windows is a separate viewing area on a computer display screen in a system.

In this case, the type of physical drives does windows disable defragmenting, but provides another method of optimization is known as windows.

Learn more about window on:

brainly.com/question/25243683

#SPJ12

4 0
2 years ago
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