Now, we know that 90°< θ <180°, that simply means the angle θ is in the II quadrant, where sine is positive and cosine is negative.
![\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{13}}\impliedby \textit{now let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem}\\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20sin%28%5Ctheta%20%29%3D%5Ccfrac%7B%5Cstackrel%7Bopposite%7D%7B5%7D%7D%7B%5Cstackrel%7Bhypotenuse%7D%7B13%7D%7D%5Cimpliedby%20%5Ctextit%7Bnow%20let%27s%20find%20the%20%5Cunderline%7Badjacent%20side%7D%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ctextit%7Busing%20the%20pythagorean%20theorem%7D%5C%5C%5C%5C%0Ac%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20%5Cpm%5Csqrt%7Bc%5E2-b%5E2%7D%3Da%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0Ac%3Dhypotenuse%5C%5C%0Aa%3Dadjacent%5C%5C%0Ab%3Dopposite%5C%5C%0A%5Cend%7Bcases%7D)
First, reflect the triangle across x
Then translate the triangle 1 unit to the right and 9 units down
Since we are converting meters to centimeters we are converting large to small.
Expect the answer to be a larger number. Here are some example of large to small:
2 weeks (larger unit) = 14 days (smaller unit) 14 is larger than 2
4 days (larger unit ) = 96 hours (smaller unit) 96 is larger than 4
Since there are 100cm in a meter, when we change meters to cm, we need a bigger number. The conversion factor is 100 and should be used as a multiplier.
Example: 47m x 100 = 4700 cm
Answer:
Step-by-step explanation:
There is really no way to show that of I know of without drawing it but here is this. I hope this helps and not really exact on position but that is very close.
Since a line =180 degrees you could set it up as (180-85) and you would get <u><em>95.
Hope this helps!!!</em></u>