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3 years ago

Can some one help me ???

Mathematics

1 answer:

babymother [125]3 years ago

5 0

The 4th option is correct

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Decimal. 08 is 10 times as much as

Ksivusya [100]

Obviously, 0.8, all you do is move over the decimal.

7 0

3 years ago

Which equation represents the vertical asymptote of the graph?

Annette [7]

The curve is y equals 0 from negative x to negative y near x equals negative 8.

If a curve has Vertical Asymptote i.e the line x=p,it is never touched by the given curve.The curve remains almost parallel to the line x=p, till the end.The two i.e a line and curve will never meet each other.

→ x is almost equal to p but not p.

so in the denominator , it is x=-8,

Vertical Asymptote occurs when we put , denominator of curve=0.

so vertical asymptote of curve is : x= -8

8 0

3 years ago

Don't have clue how to do this...

Nimfa-mama [501]

I hope this explains it

6 0

3 years ago

Solve the equation. Check your solution. 3x - 2 = 16

DedPeter [7]

X=6

16 plus 2 is 18 and divided by 3 is 6

3 0

3 years ago

Read 2 more answers

1.What is the equation of the line perpendicular to that passes through ? Write your answer in slope-intercept form. Show your

Juliette [100K]

Answer:

1. Use a compass to make arc marks which intersect above and below then connect.

2. $y=\frac{1}{3}x + 2$

Step-by-step explanation:

1. To construct a perpendicular line, use a compass to draw arc marks from one end of the segment through point P. Then repeat this again at the other end. This means at point P there will be two intersecting arc marks. Repeat the process down below with the same radius as used above. Then connect the two intersections.

2. The point slope form of a line is $(y-y_1)=m(x-x_1)$ where $x_1=-3\\y_1=1$ . We write

$(y-1)=m(x--3)\\(y-1)=m(x+3)$

Since the line is to be perpendicular to the line shown it will have the negative reciprocal to the slope of the function 3x+y =-8. To find m, rearrange the function to be y=-8-3x. The slope is -3 and the negative reciprocal will be 1/3.

$(y-1)=\frac{1}{3}(x+3)$

Simplify for slope intercept form.

$(y-1)=\frac{1}{3}(x+3)\\(y-1)=\frac{1}{3}x+1\\y=\frac{1}{3}x + 2$

3 0

3 years ago