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ASHA 777 [7]
3 years ago
14

Factor the GCF: 12a3b + 8a2b2 − 20ab3

Mathematics
2 answers:
Harrizon [31]3 years ago
6 0
<span>12a^3b + 8a^2b^2 − 20ab^3

</span>12a^3b = 4ab(3a^2)
8a^2b^2 = 4ab(2ab)
20ab^3 = 4ab(5b^2)

GCF = 4ab

12a3b + 8a2b2 − 20ab3 = 4ab(3a^2 + 2ab - 5b^2)
Rudiy273 years ago
6 0

Answer:

The GCF of given expression is 4ab.

Step-by-step explanation:

The given expression is

12a^3b+8a^2b^2-20ab^3

The factor form of each term is

12a^3b=2\times 2\times 3\times a\times a\times a\times b

8a^2b=2\times 2\times 2\times a\times a\times b\times b

-20ab^3=-2\times 2\times 5\times a\times b\times b\times b

The common factors are 2,2,a,and b.

The GCF of given expression is

12a^3b=2\times 2\times a\times b=4ab

Therefore the GCF of given expression is 4ab.

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One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second
algol13

Answer:

Therefore the third container contains   \frac{735}{17}\% = 43.23 %  acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

= (V\times \frac{100+55}{100})   cubic unit.

=\frac{155}{100}V  cubic unit.

The amount of acid in first container is

=V\times \frac{25}{100}  cubic unit.

=\frac{25}{100}V  cubic unit.

The amount of acid in second container is

=(\frac{155}{100}V \times \frac{55}{100}) cubic unit.

=\frac{8525}{10000}V cubic unit.

Total amount of acid =(\frac{25}{100}V+\frac{8525}{10000}V) cubic unit.

                                   =(\frac{2500+8525}{10000}V) cubic unit.

                                   =(\frac{11025}{10000}V)cubic unit.

Total volume of mixture =(V+\frac{155}{100}V) cubic unit.

                                       =\frac{100+155}{100}V cubic unit.

                                       =\frac{255}{100}V  cubic unit.

The amount of acid in the mixture is

=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%

=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%

=\frac{735}{17}\%

Therefore the third container contains  \frac{735}{17}\%  acid.

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