OK first convert one of the equations into Y=MX+b form
Y-2x = 3
Add 2X
Y = 2x +3
Now substitute this equation in the other one.
So it would be
3X - 2Y = 5
3X-2(2x+3) = 5
Now solve for y
3X - 4X - 6 = 5
-1X - 6 = 5
Add 6
-1X = 11
X = -11
Now substitute this into one of the equations
Y - 2X = 3
Y -2(-11) = 3
Y +22 = 3
y = 3-22
y = -19
Divide 6 by -8 to get the variable alone!
6/-8 < division< equation
Answer:
Therefore the third container contains
= 43.23 % acid.
Step-by-step explanation:
Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.
Let the volume of first container be x cubic unit.
Since the volume of second container is 55% larger than the first.
Then the volume of the second container is
cubic unit.
cubic unit.
The amount of acid in first container is
cubic unit.
cubic unit.
The amount of acid in second container is
cubic unit.
cubic unit.
Total amount of acid
cubic unit.
cubic unit.
cubic unit.
Total volume of mixture
cubic unit.
cubic unit.
cubic unit.
The amount of acid in the mixture is



Therefore the third container contains
acid.