Answer:
There are many factors that cause aggregate demand to shift from AD to AD1. The unemployment rate will fall and inflation will increase.
<u>Explanation:</u>
A Shift in aggregate demand from AD to AD1 means there has been a fall in demand. Various factors that cause demand to decrease are:
- Increase in price of a good itself
- Increase in the price of complimentary goods-This will lead to a fall in demand. Like ink and pen are complementary goods. if the Price of ink increases then demand for pen will decrease.
- A Decrease in the price of substitute goods-Like tea and coffee.
- Expectation regarding future fall in price
So due to the decrease in demand finally the unemployment will increase and with that, the inflation rate will increase making things dearer.
num1 = float(input("Enter the first number: "))
num2 = float(input("Enter the second number: "))
operation = input("Which operation are you performing? (a/s/m/d) ")
if operation == "a":
print("{} + {} = {}".format(num1, num2, num1+num2))
elif operation == "s":
print("{} - {} = {}".format(num1, num2, num1-num2))
elif operation == "m":
print("{} * {} = {}".format(num1, num2, num1*num2))
elif operation == "d":
print("{} / {} = {}".format(num1, num2, num1/num2))
I hope this helps!
Answer:
Option A is correct
Digital Subscriber line is a way where telephone companies provide internet access for connection.
It is a communication medium used to transfer digital signals. DSL is one of the most popular broadband internet access.
Explanation:
DSL stands for Digital Subscriber Line. DSL works with high-speed bandwidth that connects from a phone jack to a telephone network. DSL works within frequencies. You can use the DSL while making phone calls.
Answer:
(a) What is the best case time complexity of the algorithm (assuming n > 1)?
Answer: O(1)
(b) What is the worst case time complexity of the algorithm?
Answer: O(n^4)
Explanation:
(a) In the best case, the if condition will be true, the program will only run once and return so complexity of the algorithm is O(1)
.
(b) In the worst case, the program will run n^4 times so complexity of the algorithm is O(n^4).
