Answer:
see explaination
Explanation:
The following code is in python 3.5 and above:
# Create a main method
def main():
# Accept name from the user
name = input("Enter your name: ")
# Accept describe yourself from the user.
describe = input("Describe yourself: ")
# Create a file object
f = open('person.html','w')
# Creat a string to store the html script.
message = """<html>
<head>
</head>
<body>
<center>
<h1>"""+name+"""</h1>
</center>
<hr/>"""+describe+"""<hr/>
</body>
</html>"""
f.write(message)
f.close()
main()
Available options
=A4&&B4
=A4&" "&B4
="A4"&""&"34"
=A4&""&B4
Answer:
=A4&""&B4
Explanation:
In a Microsoft Excel spreadsheet, to combine the content of two cells into another cell, a user will have to use the command &
Hence, in this case, given that there is no need to have any character or blank space in between the content of the starging cells, which is just A4 and B4, then we have the following technique
1. Select the cell C2
2. Input the command = or +, then select cell A4
3. Input the command &
4. Then select the cell B4
5. Click enter.
Therefore, the answer should appear as =A4&B4.
But from the available options, there is nothing like that, so we pick =A4&""&B4 because it gives the same outcome.
When using screwdrivers you should always be aware that the screwdriver blade might slip out of the slot and strike you in the:
<h3>What is a Screwdriver?</h3>
A screwdriver is said to be a kind of a modern tool that can come in a manual or powered type and it is one that is often used for turning screws.
Note that a typical simple screwdriver is one that has a handle as well as a shaft and it is also one that is often ending in a tip where a given user can be able to put their hands into the screw head before turning the handle.
Therefore, when using screwdrivers you should always be aware that the screwdriver blade might slip out of the slot and strike you in the:
Learn more about screwdrivers from
brainly.com/question/20717091
#SPJ4
Answer:
#include <iostream>
using namespace std;
class Str{ ///baseclass
public :
string super_str;
string getStr()
{
return super_str;
}
void setStr(string String)
{
super_str=String;
}
};
class str : public Str{ //inheriting Str publicly
public :
string sub_str;
string getstr()
{
return sub_str;
}
void setstr(string String)
{
sub_str=String;
}
bool notstartswith()
{
int n=sub_str.length(); //to find length of substr
bool flag=false;
for(int i=0;i<n;i++) //Loop to check beginning of Str
{
if(super_str[i]!=sub_str[i])
{
flag=true;
break;
}
}
return flag;
}
};
int main()
{
str s; //object of subclass
s.setStr("Helloworld");
s.setstr("Hey");
if(s.notstartswith()==1) //checking if str is substring of Str
cout<<"Str does not start with str";
else
cout<<"Str starts with str";
return 0;
}
OUTPUT :
Str does not start with str
Explanation:
Above program is implemented the way as mentioned. for loop is being used to check the beginning of the str starts with substring or not.
Void test(char *s)
{
int i, d;
sscanf(s, "%i", &i);
printf("%s converts to %i using %%i\n", s, i);
sscanf(s, "%d", &d);
printf("%s converts to %d using %%d\n", s, d);
}
int main()
{
test("123");
test("0x123");
return 0;
}
outputs:
123 converts to 123 using %i
123 converts to 123 using %d
0x123 converts to 291 using %i
0x123 converts to 0 using %d
As you can see, %i is capable of parsing hexadecimal, whereas %d is not. For printf they're the same.
