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3 years ago

Balancing chemical equations

1 answer:

7 0

. ...
Example 2. Zn + HCl ---> ZnCl2 + H2 ...
Example 3. Ca(OH)2 + H3PO4 ---> Ca3(PO4)2 + H2O. ...
Example 4. FeCl3 + NH4OH ---> Fe(OH)3 + NH4Cl. ...
Example 5. S8 + F2 ---> SF6 ...
Example 6. C2H6 + O2 ---> CO2 + H2O. ...
Example 7. Al2(CO3)3 + H3PO4 ---> AlPO4 + CO2 + H2O. Summary
To be useful, chemical equations must always be balanced. Balanced chemical equations have the same number and type of each atom on both sides of the equation.
The coefficients in a balanced equation must be the simplest whole number ratio. Mass is always conserved in chemical reactions. mber of atoms of each element in reactants is not equal to the number of atoms of each element present in product, then the chemical equation is called unbalanced chemical equation. An equation is balanced when the same number of each element is represented on the reactant and product sides. Equations must be balanced to accurately reflect the law of conservation of matter.

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Answer:

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Step-by-step explanation:

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4 years ago

At a manufacturing plant where switches are made, it is a known fact that 2% of all switches are defective. If two switches are

olchik [2.2K]

Answer:

The probability that exactly one switch is good is

$P(x) =0.0392$

Step-by-step explanation:

The probability that a switch is defective is:

$P(D) = \frac{2}{100} =0.02$

The probability that a switch is not defective is

$P(D') = 1-P(D)=0.98$

Therefore, if two switches are selected, the probability that exactly 1 is good is:

$P(1=1)=P (D) P (D ') + P (D') P (D)$

$P(x)=(0.02)(0.98) + (0.98)(0.02)$

$P(x) =0.0392$

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4 years ago

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1) A ball is dropped from a height of 50 feet. How long after it is dropped will it reach a height of 18 feet?

Nookie1986 [14]

Answer: 1.41 seconds

Step-by-step explanation:

The problem gives the initial velocity by saying "dropped." This indicates a velocity of zero. Acceleration can also be found because the object is in free fall. It would experience the acceleration of gravity. We can use the kinematic equation:

$(y_f-y_i)=V_it+\frac{1}{2}at^2$

The velocity term completely cancels because the object was dropped with an initial velocity of 0.

$(18-50)=\frac{1}{2} (32.17)t^2\\$

$-32=-16.085t^2\\t=\sqrt{1.989} =1.41s$

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3 years ago