Answer:
The question is incomplete, this is the complete question.;
There are five nickels, five dimes and five quarters in your pocket. You randomly pick three coins and place them on the counter the first coin is a nickel, the second is a dime and the third is a quarter.find the probability of this occurring.
The answer to the question is;
the probability of this occurring is 1/27
Step-by-step explanation:
Let n(N) =5 ( the number of nickels)
n(D) =5 ( the number of dimes) and
n(Q) = 5 ( the number of quarters)
P(N)= 5/15=1/3 (prob of picking a nickel)
P(D) =5/15=1/3 (prob of picking a dime)
P(Q) = 5/15= 1/3 (prob of picking a quatre)
The probability of picking the three= P(N)×P(D)×P(Q)
= 1/3×1/3×1/3
= 1/27
let the number is 10x + 3.
then sum of its digits = x + 3.
from given condition, we have
x+3 = (1/7)* (10x + 3)
=> 7x + 21 = 10x + 3
=> 3x = 18
=> x = 6
therefore the number is 63.
The volume of a cylinder can be calculated by the product of the area of the base times the height of the shape. It is expressed as follows:
V = πr²h
We calculate as follows:
320π in³= π (r²) (5 in)
64 in² = r²
r = 8 in
Hope this answers the question. Have a nice day.
Answer:
4
Step-by-step explanation:
(3 - 5)^2
-2^2 = 4
